3 years ago

If f(z)= sqrt z2+8z , then how much does f(z) increase as z goes from 7 to 8?

Mathematics

1 answer:

Nuetrik [128]3 years ago

3 0

Answer:

Step-by-step explanation:

$f(7)=\sqrt{7^2+8*7}=\sqrt{49+56}=\sqrt{105} \approx 10.247\\f(8)=\sqrt{8^2+8*8}=\sqrt{128}=8\sqrt{2} \approx 11.314\\f(8)-f(7)=11.314-10.247=1.067 \approx 1.07$

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