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jek_recluse [69]
3 years ago
10

Which of the following statements contain a variable? Check all that apply.

Mathematics
1 answer:
fredd [130]3 years ago
5 0
D but im not sure if im right
You might be interested in
I need some help solving for x! Thanks :)
slega [8]

Given:

The figure of a rhombus.

To find:

The value of x.

Solution:

We know that, if two lines intersect each other, then the vertically opposite angles are equal.

From the given figure it is clear that the diagonals intersect each other and construct two pairs of vertically opposite angles.

Since 95^\circ and x^\circ are vertically opposite angles, therefore

x^\circ=95^\circ

Hence, the value of x is 95°.

3 0
2 years ago
Brent created a mural, 4/5 of which he painted in shades of blue. Three eighths of the blue area is sky blue. What portion of th
Snezhnost [94]

Answer: \frac{3}{10} of the mural is sky blue.


Step-by-step explanation:

Let x be the full portion of mural.

Since, \frac{4}{5} of mural is painted in shades of blue.

Therefore, the blue portion=\frac{4}{5}x

Also, Three eighths of the blue area is sky blue.

Therefore, the portion of the mural is sky blue=\frac{3}{8}\times\frac{4}{5}x

The portion of the mural is sky blue=\frac{12}{40}x

Simplify, by dividing numerator and denominator by 4, we get

The portion of the mural is sky blue=\frac{3}{10}x


5 0
2 years ago
It costs 135.25 for 15 child tickets ti the museum.Adult tickets cost 12.95 each. Find the cost for 40 children to attend along
Masja [62]

Answer:the cost for 40 children to attend along with 5 adult tickets = $ 417.55

Step-by-step explanation:

It costs 135.25 for 15 child tickets to the museum. Let us determine the cost per child ticket to the museum.

cost per child ticket to the museum.

= total cost of 15 child tickets / number of child tickets.

= 132.25 / 15 = 8.82

Adult tickets cost 12.95 each.

The cost of 40 child tickets is

40 × 8.82 = $352.8

The cost of 5 adult tickets = 5 × 12.95

=$ 64.75

the cost for 40 children to attend along with 5 adult tickets would be

352.8 + 64.75 = $ 417.55

4 0
2 years ago
A class has 35 students, of which 16 are male and 19 are female. If 6 of the students are selected at random to form a committee
madreJ [45]

Answer:

The probability of choosing exactly 2 male and 4 female students =\frac{\binom{16}{2}\times \binom{19}{4}}{\binom{35}{6}}

Step-by-step explanation:

We are given that a class has 35 students

Number of male=16

Number of female=19

We have to choose 6 students for committee

We have to find the probability that exactly 2 male students are selected

Probability=P(E)=\frac{number\;of\;favorable\;cases}{total\;number\;of\;cases}

If we have to choose total 6 student in which 2 male and 4 female

Combination formula:

nC_r=\frac{n!}{r!(n-r)!}

Using the formula

The probability of choosing exactly 2 male and 4 female students =\frac{\binom{16}{2}\times \binom{19}{4}}{\binom{35}{6}}

5 0
2 years ago
Can y’all please help me
Viefleur [7K]

Step-by-step explanation:

19.50 i got that if i got it wrong mb

8 0
3 years ago
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