Answer:
<em>The true statements are:</em>
<em>*The median weight for shelter A is greater than shelter B.</em>
<em>*The (IQR) interquartile range of shelter A is greater than the (IQR) interquartile range of shelter B.</em>
Step-by-step explanation:
<em>(for shelter A)</em>
median: 21
lowest value: 8
highest value: 30
lower quartile: 17
upper quartile: 28
(IQR) interquartile range: 28 - 17 = 11
Range: 30 - 8 = 22
<em>(for shelter B)</em>
median: 18
lowest value: 10
highest value: 28
lower quartile: 16
upper quartile: 20
(IQR) interquartile range: 20 - 16 = 4
Range: 28 - 10 = 18
~phew!, this took me long xd, hope this helps you~
I would highly appreciate it if you would mark me the brainliest~ :)
Answer:
x = -3
y = -1
Step-by-step explanation:
in the given question :-
=》x - 4y = 1
=》x = 4y + 1
now replacing the value of x as ( 4y + 1 ) in equation (2)
=》3x + 2y = -11
=》3 (4y + 1) + 2y = -11
=》12y + 3 + 2y = -11
=》14y = -11 - 3
=》y = -14 ÷ 14
=》y = -1
now, putting the value of y in equation (1)
=》x - 4y = 1
=》x - ( 4 × -1 ) = 1
=》x + 4 = 1
=》x = 1 - 4
=》x = -3
Answer:
depands
Step-by-step explanation:
on how much ppl
Answer:
1/6 of a cup of milk. Or at least that's my answer.
Step-by-step explanation:
Okay, we need to find out 25% of 2/3.
25% of 2/3 is 1/6.
Let the required point be (a,b)
The distance of (a,b) from (7,-2) is
= 
But this distance needs to be betweem 50 & 60
So
Squaring all sides
2500 < (a-7)² + (b+2)² < 3600
Let a = 7
So we have
2500 < (b+2)² <3600
b+2 < 60 or b+2 > -60 => b <58 or b > -62
Also
b+2 >50 or b + 2 < -50 => b >48 or B < -52
Let us take one value of b < 58 say b = 50
So now we have the point as (7, 50)
The other point is (7,-2)
Distance between them
= 
This is between 50 & 60
Hence one point which has a distance between 50 & 60 from the point (7,-2) is (7, 50)
