Answer:
The diagonals of a rectangle are always congruent
There are 10,000 total four-digit numbers (1000 through 9999).
Multiples of 2 end in 0, 2, 4, 6, and 8. There are 9*10*10*5 = 4500 four-digit multiples of 2.
Multiples of 5 end in 0 or 5. There are 9*10*10*2 = 1800 four-digit multiples of 5.
There is redundancy between the two sets of numbers, namely those that end in 0, which are both multiples of 2 and 5. There are 9*10*10*1 = 900 four-digit multiples of both 2 and 5.
Then there are 4500 + 1800 - 900 = 5400 total four-digit numbers that are either multiples of 2 or 5, which means the remaining 4600 numbers are neither multiples of 2 nor 5.
Answer: 38090 fish
Step-by-step explanation:
Use the equation 55,000(.96)^9. Start with the initial number in this case it is 55,000 then multiply by the percentage that remains (100% - 4% = 96%) and then put it to the ninth power because that is how many years the problem is asking for.
