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masya89 [10]
4 years ago
9

Find the ordered pairs for the x- and y-intercepts of the equation 5x − 6y = 30 and select the appropriate option below.

Mathematics
2 answers:
Amiraneli [1.4K]4 years ago
7 0
5x - 6y = 30
6y = 5x - 30
Y = 5/6x - 5
y intercept = -5
Therefore (0, -5)

0 = 5/6x - 5
5/6x = 5
x = 6
x intercept = 6
therefore (6,0)

answer : first one 
x intercept =
Darina [25.2K]4 years ago
5 0
For finding the x intercept 
y=0, 5x-6*0=30, x=30:5, x= 6 ⇒ (6,0)- the x intercept

for y intercept, x=0
5*0-6y=30, -6y=30, y= - 30/6, y= - 5 ⇒ (0, -5 ) - the y intercept

the first is correct answer
EagleGaming
2 years ago
wrong
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Need help please and fast thank you
shtirl [24]

Answer:

The second batch

Step-by-step explanation:

7 0
3 years ago
Se vende2 usb en 60 soles cada uno. En una se ganó el 20% y en la otra se perdió el 20% ¿Se ganó o se perdió en total y cuánto?
aniked [119]
Voy a responder en el mismo idioma en que está la pregunta.

1) Venta con ganancia

Precio de venta 60 soles.

Ganancia = 20% del costo => costo + 0,20 * costo =  precio

=> costo (1 + 0,20) = precio = 60 soles

=> costo (1,20) = 60 soles => costo = 60 soles / 1,20 = 50 soles

2) Venta con pérdida del 20%

Pérdida = 20% del costo

=> costo - precio = 20% * costo => costo - 0,20*costo = precio

=> costo ( 1 - 0,20) = 60 soles => costo * 0,80 = 60 soles

=> costo = 60 soles / 0,80 = 75 soles

3) Costo total = 50 soles + 75 soles = 125 soles

4) Ganancia total = valor total de venta - costo total

Ganancia total = 2 * 60 soles + 125 soles = 120 soles - 125 soles = - 5 soles.

El signo negativo significa que al final se perdió 5 soles en la operación.
8 0
4 years ago
How do i solve this?
bixtya [17]

Answer:

5.x^8.y^3

Step-by-step explanation:

15.x^10.y^5.z^2 ÷ 3.x^2.y^2.z^2

= 15/3. x^(10-2). y^(5-2). z^(2-2)

= 5.x^8.y^3.z^0

= 5.x^8.y^3

7 0
3 years ago
The graph of y = x^2 is translated 3 units to the left. The equation for this new graph is:
EastWind [94]
The answer is:
C. Y=(x+3)^2
7 0
3 years ago
What is the sum of the first 4 terms of a geometric sequence that has a first term of 2 and a ratio (multiplier) of 8?
taurus [48]

\bf \qquad \qquad \textit{sum of a finite geometric sequence} \\\\ S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad  \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ r=\textit{common ratio}\\ ----------\\ a_1=2\\ r=8\\ n=4 \end{cases} \\\\\\ S_4=2\left( \cfrac{1-8^4}{1-8} \right)\implies S_4=2\left( \cfrac{-4095}{-7} \right) \\\\\\ S_4=2(585)\implies S_4=1170

6 0
3 years ago
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