X² + x - 12 / x² - x - 20 ÷ 3x² - 24x + 45 / 12x² - 48x - 60

x² + x - 12 / x² - x - 20 * 12x² - 48x - 60 / 3x² - 24x + 45

(x² + x - 12)(12x² - 48x - 60)
(x² - x - 20)(3x² - 24x + 45)

12x^4 - 48x³ - 60x² + 12x³ - 48x² - 60x - 144x² + 576x + 720
3x^4 - 24x³ + 45x² - 3x³ + 24x² - 45x - 60x² + 480x - 900

12x^4 - 48x³ + 12x³ - 60x² - 48x² - 144x² - 60x + 576x + 720
3x^4 - 24x³ - 3x³ + 45x² + 24x² - 60x² - 45x + 480x - 900

12x^4 - 36x³ - 252x² + 516x + 720
3x^4 - 27x³ + 9x² + 435x - 900

12(x^4 - 3x³ - 21x² + 43x + 60) 
3(x^4 - 9x³ + 3x² + 145x + 300)

4(x^4 - 3x³ - 21x² + 43x + 60) 
 (x^4 - 9x³ + 3x² + 145x + 300)

4 0

3 years ago

You are playing a game in which you randomly select one square tile and one round tile from the sets shown below. Before you sel

AnnZ [28]

I think it is D
Hope my answer help you?

8 0

2 years ago

Read 2 more answers

For what values of a are the following expressions true?/a+5/=-5-a

katovenus [111]

Explanation:

The expression is given below as

$|a+5|=-5-a$

Concept:

We will apply the bsolute rule below

$\begin{gathered} if|u|=a,a>0 \\ then,u=a,u=-a \end{gathered}$

By applying the concept, we will have

$\begin{gathered} \lvert a+5\rvert=-5-a \\ a+5=-5-a,a+5=5+a \\ a+a=-5-5,a-a=5-5 \\ 2a=-10,0=0 \\ \frac{2a}{2}=\frac{-10}{2},0=0 \\ a=-5,0=0 \end{gathered}$

Hence,

The final answer is

$a\leq-5$

5 0

8 months ago