Answer: 25cm
Es asi: 5cm x 5cm^2
Answer:
Step-by-step explanation:
-2x²=-8x+8 means : -2x²+8x-8
the discrinant of the quadratic equation is : delta = b²-4ac
when a=-2 and b=8 and c= -8
calculate delta = (8)²-4(-2)(-8) ......continu
Let y(t) represent the level of water in inches at time t in hours. Then we are given ...
y'(t) = k√(y(t)) . . . . for some proportionality constant k
y(0) = 30
y(1) = 29
We observe that a function of the form
y(t) = a(t - b)²
will have a derivative that is proportional to y:
y'(t) = 2a(t -b)
We can find the constants "a" and "b" from the given boundary conditions.
At t=0
30 = a(0 -b)²
a = 30/b²
At t=1
29 = a(1 - b)² . . . . . . . . . substitute for t
29 = 30(1 - b)²/b² . . . . . substitute for a
29/30 = (1/b -1)² . . . . . . divide by 30
1 -√(29/30) = 1/b . . . . . . square root, then add 1 (positive root yields extraneous solution)
b = 30 +√870 . . . . . . . . simplify
The value of b is the time it takes for the height of water in the tank to become 0. It is 30+√870 hours ≈ 59 hours 29 minutes 45 seconds
Answer:
b. 160°
Step-by-step explanation:
angle A = (far arc - near arc)/2
far arc is arc BC and near arc is arc BE. Replacing into the equation:
∠A = (arc BC - arc BE)/2
50 = [4x + 20 - (2x - 10)]/2
50*2 = 2x + 30
x = (100 - 30)/2
x = 35°
Replacing this information into arc BC equation:
arc BC = 4(35) + 20 = 160°
Hello!
To convert degrees to radians you multiply it by
. We will do so below.
75(
)≈1.31
Therefore, the correct answer is
A.1.31 radians.
I hope this helps!
