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3 years ago

13

A music club charges an annual membership of $35.65 plus $12.99 for each CD purchased. If Naomi's total bill for the year was 17

8.54, how many CDs did she purchase.

1 answer:

Luden [163]3 years ago

6 0

Answer:

Step-by-step explanation:

178.54-35.65=142.89

then you do 142.89/12.99=11

She bought 11 CDs

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Question 4<br> What is the value of x? n10 / n12 = n*<br> need answer will mark brainlist

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Answer:

Step-by-step explanation:

$\frac{n^{10}}{n^{12}}=n^x\\n^{10-12}=n^x\\n^{-2}=n^x\\x=-2$

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10. Aman plans to spend his January salary as

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Olivia needs 54 licks for every 3 lollipop she licks

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Answer:

PLEASE BUY ME BITEABLE ACCOUNT. COSTS 19 DOLLARS! PLEASE ANYONE!

Step-by-step explanation:

To find how many licks she does to 1 lollipop, 54 divided by 3 which is 18. So, 18 licks/lollipop. 36/18=2. Which means Olivia licks 2 lollipops in 36 licks. To find 5 lollipops, 18*5=90. She licks 5 lollipops in 90 licks.

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3 years ago

You spend $3.50 on fruit. Apples cost $0.20 each while oranges cost $0.30 each. The equation models the situation, where x is th

Licemer1 [7]

Answer:

b. 11 apples; 1 orange

Step-by-step explanation:

We test each option, and see if the total is $3.50(what you spend). If the result is different, it is not a possible solution.

a. 1 apple; 11 oranges

1 apple for $0.20

11 oranges for $0.30 each

0.20 + 11*0.30 = $3.50

Possible solution

b. 11 apples; 1 orange

11 apples for $0.20 each

1 orange for $0.30

11*0.2 + 0.3 = 2.5

Not $3.5, so this is not a possible solution.

This is the answer

c. 7 apples; 7 oranges

7*0.2 + 7*0.3 = $3.5

Possible

d. 4 apples; 9 oranges

4*0.2 + 9*0.3 = $3.5

Possible

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3 years ago

B) Consider the weighted voting system (q: 8,4,2,1). Find the Banzhaf power distribution of this weighted voting systwm when q=1

pashok25 [27]

Answer:

Given : (q: 8,4,2,1)

q = 15

List all coalitions ( 2 pair)

$(P_1,P_2)=\text{Total weight }=8+4=12 \\(P_1,P_3)\text{Total weight }=8+2=10 \\(P_1,P_4)\text{Total weight }=8+1=9 \\(P_2,P_3)\text{Total weight }=4+2=6 \\(P_2,P_4)\text{Total weight }=4+1=5 \\(P_3,P_4)\text{Total weight }=2+1 = 3$

Those whose total weight is equal to q or more than q will go further in the list of winning coalitions

Since No pair's total weight is equal to q or more than q . So, we will not consider then further

Coalitions ( 3 pair or more)

$(P_1,P_2,P_3)=\text{Total weight }=8+4+2=14 \\(P_1,P_2,P_4)\text{Total weight }=8+4+1=13 \\(P_1,P_3,P_4)\text{Total weight }=8+2+1=11 \\(P_2,P_3,P_4)\text{Total weight }=4+2+1=7 \\(P_1,P_2,P_3,P_4)\text{Total weight }=8+4+2+1=15$

Those whose total weight is equal to q or more than q will go further in the list of winning coalitions

winning coalitions:

$(P_1,P_2,P_3,P_4)$

If Player 1 leaves

So, total weight will be 4+2+1 = 7

So, Player 1 is critical

If Player 2 leaves

So, total weight will be 8+2+1 = 11

So, Player 2 is critical

If Player 3 leaves

So, total weight will be 8+4+1 = 13

So, Player 3 is critical

If Player 4 leaves

So, total weight will be 8+4+2 = 14

So, Player 4 is critical

Player Times critical Banzhaf power index

1 1 $\frac{1}{4} \times 100 = 25\%$

2 1 $\frac{1}{4} \times 100 = 25\%$

3 1 $\frac{1}{4} \times 100 = 25\%$

4 1 $\frac{1}{4} \times 100 = 25\%$

Sum = 4

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3 years ago