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2 years ago

Jackson ran 2 12 miles around the track. Each lap around the track is 14 of a mile. How many laps did Jackson run?

Mathematics

1 answer:

Lemur [1.5K]2 years ago

3 0

Answer:

212/14=15

Step-by-step explanation:

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What is 3 divided by 11/12

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Answer:

0.02272

Step-by-step explanation:

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What is the difference between 9 thirty sevens and 8 thirty sevens

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What is the x coordinate of the solution? <br> What is the y coordinate of the solution?

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Step-by-step explanation:

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If we inscribe a circle such that it is touching all six corners of a regular hexagon of side 10 inches, what is the area of the

Brrunno [24]

Answer:

$\left(100\pi - 150\sqrt{3}\right)$ square inches.

Step-by-step explanation:

<h3>Area of the Inscribed Hexagon</h3>

Refer to the first diagram attached. This inscribed regular hexagon can be split into six equilateral triangles. The length of each side of these triangle will be $10$ inches (same as the length of each side of the regular hexagon.)

Refer to the second attachment for one of these equilateral triangles.

Let segment $\sf CH$ be a height on side $\sf AB$ . Since this triangle is equilateral, the size of each internal angle will be $\sf 60^\circ$ . The length of segment

$\displaystyle 10\, \sin\left(60^\circ\right) = 10 \times \frac{\sqrt{3}}{2} = 5\sqrt{3}$ .

The area (in square inches) of this equilateral triangle will be:

$\begin{aligned}&\frac{1}{2} \times \text{Base} \times\text{Height} \\ &= \frac{1}{2} \times 10 \times 5\sqrt{3}= 25\sqrt{3} \end{aligned}$ .

Note that the inscribed hexagon in this question is made up of six equilateral triangles like this one. Therefore, the area (in square inches) of this hexagon will be:

$\displaystyle 6 \times 25\sqrt{3} = 150\sqrt{3}$ .

<h3>Area of of the circle that is not covered</h3>

Refer to the first diagram. The length of each side of these equilateral triangles is the same as the radius of the circle. Since the length of one such side is $10$ inches, the radius of this circle will also be $10$ inches.

The area (in square inches) of a circle of radius $10$ inches is:

$\pi \times (\text{radius})^2 = \pi \times 10^2 = 100\pi$ .

The area (in square inches) of the circle that the hexagon did not cover would be:

$\begin{aligned}&\text{Area of circle} - \text{Area of hexagon} \\ &= 100\pi - 150\sqrt{3}\end{aligned}$ .

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3 years ago

Find the slope of the line.<br> Can somebody please help me and/ or explain ?

Olegator [25]

Answer:

4/-2

Step-by-step explanation:

Start at a point where the line intersects a firm coordinate like y=2 then use rise/run rise is vertical and run is horizontal count from the intersection up to where the line intersects another firm point in this case y=6 then count the run which lands on x=-2 y=6 which gives you the slope of 4/-2

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2 years ago