First, I'd like to say that this question is flawed because the diameter of the spool changes as you pull the line out. Some would argue it's negligible I suppose.
At any rate, assuming there's a magic spool where the diameter doesn't change, let's find the cicumference so we can find the length of one wrap around the spool.
circumference = 2*pi*r = 2 * pi * 4cm = about 25.133 cm
Now if it turns 16 times we'll have 16 times the circumference.
16 * (25.133 cm)
= 402.128 cm
Answer:
cos60°
Step-by-step explanation:
Using the cofunction identity
cos(90 - x) = sinx , then
sin30° = cos(90 - 30)° = cos60°
Answer:
Surface area of the wood to be painted = (
+ r
)
- 16
Step-by-step explanation:
Surface area of a cone is given as the sum of the surface area and the area of its base.
i.e Surface area = 
+
Lr
where: L is the length of its slant height and r is the radius.
Applying the Pythagoras theorem,
L = 
Thus,
Surface area =
r (r +
)
The given cylindrical hole has a radius of 4 cm and depth 2 cm.
The area of one of its circular surfaces = 

=
× 
= 16

The surface area of the piece of wood to be painted = surface area of cone - area of cylindrical circular surface.
Surface area of the wood to be painted =
r (r +
) - 16
Since area is length times width, it would be the factors of the equation for the area.
X2+11x+28 factors into...
Length is x+7 so...
Width is x+4
Answer:
(x - 2)^2 + (y - 2)^2 = 3
Step-by-step explanation:
The centre point of the circle is the value for x and y
And the radius is the distance from the centre to the circumference.