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3 years ago

Question in the picture

Mathematics

1 answer:

mart [117]3 years ago

8 0

I will find x, so 4x-4=180, so 4x=184, so x=46

Sorry if i answered wrong I don't understand what it is asking for.

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The half of the circle equals 764747575674 cm. <br> What's the whole circle?

Greeley [361]

Times by 2
1.529495e9 cm

3 0

3 years ago

Rectangle ABCD has vertices at (-7,-2); (1, -2); (1, -8); and (-7, -8) respectively. If GHJK is a similar rectangle where G(2, 5

Minchanka [31]

Answer:

J (6,2) K (2,2)

Step-by-step explanation:

Now distance of AB = [(y2-y1)^2 + (x2-x1)^2]^(1/2)

= 8 units

CB = [(y2-y1)^2 + (x2-x1)^2]^(1/2)

= 6 units by using same formula

Now AB/CB must equal to GH/HJ as rectangles are similar

GH = [(y2-y1)^2 + (x2-x1)^2]^(1/2)

= 4 units

8/6 = 4/HJ

So,

HJ = 3 units

Now if we see the coordinates given carefully, it is obvious that two perpendicular lines lie perfectly parallel to x and y coordinates in rectangle ABCD. A is (-7,-2) and B is (1,-2) which means distance along y-axis doesn't change. Similarly for C (1,-8) and D (-7,-8), one can see that distance between y-axis doesn't change. So lines AB and CD of rectangle are parallel with x and AD and BC are parallel with y-axis.

In rectangle GHJK one can see that in given coordinates, G(2,5) and H(6,5), y coordinate is same so it is parallel to x axis. Now, HJ is perpendicular to GH so it must be parallel to y axis. It means if we know the lengths of sides we can easily determine unknown coordinates by simple addition and subtraction.

So, we know HJ = 3 units

J is (6,2) since HJ is parallel to y axis so distance on x axis will remain unchanged and length of line HJ will effect distance of y axis.

Similarly K is (2,2) for the same reason.

6 0

3 years ago

The difference of a number and thirty-six is seven. Algebraic expression

sleet_krkn [62]

Answer:

x-36=7

Step-by-step explanation:

x-36=7

x=36+7

x=43

6 0

3 years ago

HELP ASAP. solve for x

svp [43]

Answer:

x = 80

Step-by-step explanation:

x + 30 = 110 (Opposite angles are equal)

x = 110 - 30

x = 80

4 0

3 years ago

Consider the problem of finding the line of symmetry and vertex of the quadratic equation f(x) =x^2-8x+15 What is the error in t

Jet001 [13]

We are given the quadratic:

$f(x)=x^2-8x+15$ , with a=1, b=-8, c=15.

We know that the x-coordinate of the vertex, which is the point where the line of symmetry passes through is

$\displaystyle{ -\frac{b}{2a}$ .

Thus, the x-coordinate of the vertex is $-\frac{b}{2a} =-\frac{-8}{2\cdot1}= \frac{8}{2}=4$ .

Thus, the line of symmetry is x=4.

Answer: <span>B. The line of symmetry should have been 4 instead of –4. </span>

6 0

3 years ago