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slavikrds [6]
3 years ago
7

How many seconds will it take to get to 150 feet if you can run 11 feet per second

Mathematics
2 answers:
postnew [5]3 years ago
8 0

Answer:

13.64 seconds

Step-by-step explanation:

150 / 11 = 13.636

nignag [31]3 years ago
4 0

Answer:

13.6363636364 seconds

Step-by-step explanation:

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4 years ago
Please solve, I will mark as brainlyiest if right!
finlep [7]

Answer:

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Step-by-step explanation:

5 0
3 years ago
If Josh can run 1.5 miles in 12 minutes, how long will it take him to run a mile?
olchik [2.2K]

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7 0
3 years ago
Read 2 more answers
Simplify.
Dominik [7]

Simplify: [{y^(2/7)}/{y^(1/2)}]

Since, [{a^(p/q)}/{a^(r/s)}] = a^{(p/q)-(r/s)}

Where,

  • a = p
  • p/q = 2/7 and
  • r/s = 1/2

so,

= y^{(2/7)-(1/2)}

Take the LCM of denominator i.e.,2 & 7 is 14.

= y^{(2*2 - 1*7)/14}

= y^{(4-7)/14}

= y^(-3/14) Ans.

<u>read</u><u> </u><u>more similar</u><u> questions</u><u>:</u> Which equation can be simplified to find the inverse of y = x2 – 7? a: x=y ^ 2 - 1/7 b: 1/x = y^2 - 7 c: x = y^2 – 7 d: –x = y^2 – 7..

brainly.com/question/2396514?referrer

6 0
2 years ago
Given: Elmwood St. and Oak Dr. are the same distance. All intersections are perpendicular.
vlabodo [156]

Answer:

The above result is proved with the help of Pythagoras theorem and explained below.

Step-by-step explanation:

Given figure ABCD in which AD=BC and all angles intersect at right angle. Hence, the triangle formed inside ADC and ABC are right angled triangle.

In triangle ADC,

By applying Pythagoras theorem, we get

AC^{2}=AD^{2}+DC^{2}    →  (1)

In triangle ABC,

AC^{2}=AB^{2}+BC^{2}    →  (2)

Now, from eq (1) and (2)

Peach Tree Dr. is the same distance as Sycamore Ln.


AD^{2}+DC^{2} = AB^{2}+BC^{2}

⇒ DC^{2} = AB^{2}              (∵ AD=BC)

⇒ DC=AB                    (∵Distance can never negative)

Therefore, Peach Tree Dr. is the same distance as Sycamore Ln.


8 0
3 years ago
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