Answer:
b = ±16
Step-by-step explanation:
Normally to find the number we add to make it a perfect square
We take the coefficient of x
b
Divide by 2
b/2
Then square it
(b/2) ^2
In this case, we are adding 64
(b/2) ^2 = 64
Take the square root of each side
sqrt((b/2) ^2) = sqrt(64)
b/2 = ±8
Multiply each side by 2
b/2*2 = ±8 *2
b = ±16
Vertex: (-5,-2); parabola opens up;
General form of the equation for a vertical parabola opening up is:
y-k = a(x-h)^2; knowing that the vertex is at (-5,-2), we can write:
y+2 = a(x+5)^2. We need to find the value of the coefficient a.
From the graph we see that y is 10 when x is approx. -1 3/4 (or -7/4).
subst. these values into y+2 = a(x+5)^2, we get:
10 + 2 = a(-7/4 + 5)^2, or 12 = a(13/4)^2, or 1 = a(169/16).
Solving for a: a = 16/169 = 0.09, or approx 16/160, or 1/10. Unfortunately, this is not close to any of the four answer choices.
I thought it best to try again, and fortunately my second try was correct:
10+2 = a(13/4)^2, or (169/16)a. Thus, 12 = a(169/16)
12
Solving for a: a = ------------- = 1.14. The answer choice closest to this is 1.
169/16
Answer A is correct.
-6 and -8.
Set as x and x-2
Create an equation of 3(x) = (x-2)-10
Solve, x = -6.
So, x-2 = -8.
Answer:
1
Step-by-step explanation:
Area of Triangle = 1/2 x Base x Height = 1/2 x 16 x 1/8 =1
Hey, I suggest checking out tiger algebra, this is the answer I got from the site :
