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Dima020 [189]
2 years ago
13

Write an equation of a line through (4,-1), parallel to y = 1x – 5​

Mathematics
1 answer:
Mashcka [7]2 years ago
5 0
Y=1x -1

this is because you only change the z intercept when lines are parallel
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Please help me is due today and I am being timed
ivanzaharov [21]

Answer:

B

Step-by-step explanation:

3 0
3 years ago
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What is the answer to y divided by 2 = 17
bija089 [108]
The answer is Y=34
Because 34/17 is 34
7 0
3 years ago
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Need an answer as soon as possible.
Elza [17]
Part A

Answer: The common ratio is -2

-----------------------------------

Explanation: 

To get the common ratio r, we divide any term by the previous one

One example:
r = common ratio
r = (second term)/(first term)
r = (-2)/(1)
r = -2

Another example:
r = common ratio
r = (third term)/(second term)
r = (4)/(-2)
r = -2
and we get the same common ratio every time

Side Note: each term is multiplied by -2 to get the next term

============================================================
Part B

Answer:
The rule for the sequence is 
a(n) = (-2)^(n-1)
where n starts at n = 1

-----------------------------------

Explanation:

Recall that any geometric sequence has the nth term
a(n) = a*(r)^(n-1)
where the 'a' on the right side is the first term and r is the common ratio

The first term given to use is a = 1 and the common ratio found in part A above was r = -2
So,
a(n) = a*(r)^(n-1)
a(n) = 1*(-2)^(n-1)
a(n) = (-2)^(n-1)

============================================================
Part C

Answer: The next three terms are 16, -32, 64

-----------------------------------

Explanation:

We can simply multiply each previous term by -2 to get the next term. Do this three times to generate the next three terms

-8*(-2) = 16
16*(-2) = -32
-32*(-2) = 64

showing that the next three terms are 16, -32, and 64

An alternative is to use the formula found in part B

Plug in n = 5 to find the fifth term
a(n) = (-2)^(n-1)
a(5) = (-2)^(5-1)
a(5) = (-2)^(4)
a(5) = 16 .... which matches with what we got earlier

Then plug in n = 6
a(n) = (-2)^(n-1)
a(6) = (-2)^(6-1)
a(6) = (-2)^(5)
a(6) = -32 .... which matches with what we got earlier

Then plug in n = 7
a(n) = (-2)^(n-1)
a(7) = (-2)^(7-1)
a(7) = (-2)^(6)
a(7) = 64 .... which matches with what we got earlier

while the second method takes a bit more work, its handy for when you want to find terms beyond the given sequence (eg: the 28th term)
6 0
3 years ago
What has the sum of 20 but the difference is 8?
arlik [135]
X + y = 20---- 1
x - y = 8----- 2

From 1+2
2x = 28
x = 14
Substitute x in eq.2
14 -y = 8
y = 6

Ans : x= 14 , y= 6
6 0
3 years ago
5y(2x-1)=y(x+2)+20, x=3​
Shkiper50 [21]

Answer:

y=1

Step-by-step explanation:

5y(2x-1)=y(x+2)+20, x=3

5y(2(3)-1)=y(3+2)+20

5y(6-1)=y(5)+20

5y(5)=5y+20

25y=5y+20

25y-5y=20

20y=20

y=20/20

y=1

4 0
3 years ago
Read 2 more answers
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