Answer:
The 99% confidence interval for the proportion of the population who are obese is (0.25, 0.282)
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
For this problem, we have that:
99% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
The lower limit of this interval is:
The upper limit of this interval is:
The 99% confidence interval for the proportion of the population who are obese is (0.25, 0.282)
Answer:
P(0) = 2000
P(10) = 2414
Step-by-step explanation:
The price for today is given by P(t) when t=0. Put 0 where t is, and do the arithmetic.
P(0) = 2000·1.019^0 = 2000
The price in 10 years is given by P(t) when t=10. Put 10 where t is, and do the arithmetic.
P(10) = 2000·1.019^10 ≈ 2000·1.207096 ≈ 2414
We know that In right angle triangle c^2 = a^2 + b^2.
19^2 = 3^2 + b^2
b = (361 - 9)^1/2 = 18.761663039294
Now for angles
sin(A) = a/c = 3/19
A = sin{-1}(3/19) = 9.0847202873911
A = 9.0847202873911
sin(B) = b/c = 18.761663039294 / 19
B = sin{-1}(18.761663039294 / 19) = 80.915279712614
B = 80.915279712614
