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3 years ago

A rectangle has a length of 9 and a width of 7. Find the length of the diagonal. (Hint: Use

Mathematics

1 answer:

ankoles [38]3 years ago

3 0

The answer is:
c = 11.40175425
or
c = 11.4

diagram and Pythagorean :

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Please do first question AND HURRY.

sweet-ann [11.9K]

The picture is cut off. We can't solve :/

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3 years ago

A group of neighbors is holding an end of summer block party. They buy ppp packs of hot dogs, with 888 hot dogs in each pack. Al

Ann [662]

Answer:

56 ÷ 8 = p

Step-by-step explanation:I

If you want to find how many packs there are, it would be 56 divided by 8 would equal p.

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3 years ago

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Write the number in expanded 280.34

BARSIC [14]

Answer:

200+80+4+0.3+0.04

Step-by-step explanation:

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3 years ago

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The figures below are made out of circles, semicircles, quarter circles, and a square. Find the area and the perimeter of each f

WITCHER [35]

Answer:

Part 1) $A=36(\pi-2)\ cm^2$

Part 2) $P=6(\pi+2\sqrt{2})\ cm$

Step-by-step explanation:

The picture of the question in the attached figure

Part 1) Find the area

we know that

The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle

$A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)$

we have that the base and the height of triangle is equal to the radius of the circle

$r=12\ cm\\b=12\ cm\\h=12\ cm$

substitute

$A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)\\A=(36\pi-72)\ cm^2$

simplify

Factor 36

$A=36(\pi-2)\ cm^2$

Part 2) Find the perimeter

The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle

The circumference of a quarter of circle is equal to

$C=\frac{1}{4}(2\pi r)=\frac{1}{2}\pi r$

substitute the given values

$C=\frac{1}{2}\pi (12)\\C=6\pi\ cm$

Applying the Pythagorean Theorem

The hypotenuse of right triangle is equal to

$AC=\sqrt{12^2+12^2}\\AC=\sqrt{288}\ cm$

simplify

$AC=12\sqrt{2}\ cm$

Find the perimeter

$P=(6\pi+12\sqrt{2})\ cm$

simplify

Factor 6

$P=6(\pi+2\sqrt{2})\ cm$

4 0

4 years ago

Help please! 6x^2+2x-9=0 A 6.4, -8.4 B 1.1, -1.4 C -2.2, 2.8 D -1.1, -1.4

Yakvenalex [24]

$6x^2+2x-9=0\\\\a=6;\ b=2;\ c=-9\\\\\Delta=b^2-4ac\to\Delta=2^2-4\cdot6\cdot(-9)=220\\\\x_1=\dfrac{-b-\sqrt\Delta}{2a};\ x_2=\dfrac{-b+\sqrt\Delta}{2a}\\\\x_1=\dfrac{-2-\sqrt{220}}{2\cdot6}=\dfrac{-2-\sqrt{220}}{12}\approx-1.4\\\\x_2=\dfrac{-2+\sqrt{220}}{2\cdot6}=\dfrac{-2+\sqrt{220}}{12}\approx1.1$

Answer: B. 1.1; -1.4.

6 0

3 years ago