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Lina20 [59]
3 years ago
5

What is the derivative of y=(4x+1)(1-x)^3

Mathematics
1 answer:
Rudik [331]3 years ago
6 0
I am not so sure of this but I feel it would serve as hint

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PLEAS HELP ILL GIVE BRAINLIEST<br> PLEASE SHOW WORK
ololo11 [35]

Answer: its A

Step-by-step explanation:

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Help me please thank you!!
Alexxandr [17]

The answer to your problem is A because you must add them altogether but i might be wrong im just trying to help you out

5 0
3 years ago
A 10 2/3 inch long pipe is cut into 8 equal length pieces, how long is each piece​
storchak [24]

Answer:

\frac{4}{3} inches

Step-by-step explanation:

The total length of pipe is  10  2/3rd inches

It is cut into 8 equal pieces

We need to divide total length by 8 to get length of each piece. First, we have to convert mixed number (total length) to improper fraction by using formula shown below:

a\frac{b}{c}=\frac{(a*c)+b}{c}

So,

10\frac{2}{3}=\frac{32}{3}

Each piece length is:

\frac{\frac{32}{3}}{8}\\=\frac{32}{3}*\frac{1}{8}\\=\frac{32}{24}\\=\frac{4}{3}

So, each piece is \frac{4}{3} inches

6 0
3 years ago
Write a related addition equation for the subtraction equation.
Bess [88]

Answer:

-7+12 will also give u 5 with a positive sign

8 0
3 years ago
Suppose the weights of apples are normally distributed with a mean of 85 grams and a standard deviation of 8 grams. The weights
user100 [1]

Answer:

a) 0.0304 = 3.04% probability a randomly chosen apple exceeds 100 g in weight.

b) The weight that 80% of the apples exceed is of 78.28g.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Weights of apples are normally distributed with a mean of 85 grams and a standard deviation of 8 grams.

This means that \mu = 85, \sigma = 8

a. Find the probability a randomly chosen apple exceeds 100 g in weight.

This is 1 subtracted by the p-value of Z when X = 100. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{100 - 85}{8}

Z = 1.875

Z = 1.875 has a p-value of 0.9697

1 - 0.9696 = 0.0304

0.0304 = 3.04% probability a randomly chosen apple exceeds 100 g in weight.

b. What weight do 80% of the apples exceed?

This is the 100 - 80 = 20th percentile, which is X when Z has a p-value of 0.2, so X when Z = -0.84.

Z = \frac{X - \mu}{\sigma}

-0.84 = \frac{X- 85}{8}

X - 85 = -0.84*8

X = 78.28

The weight that 80% of the apples exceed is of 78.28g.

5 0
3 years ago
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