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Paraphin [41]
3 years ago
8

What is the range of the function graphed below? PLEASE ANSWER ASAP

Mathematics
1 answer:
jenyasd209 [6]3 years ago
6 0
<h3>Answer: Choice C) -\infty < y < 2</h3>

This is a more complicated way to write y < 2

The range is the set of all possible y outputs of a function. So we use the graph to see what y values are possible. The graph shows that y can be anything smaller than y = 2. We can't actually reach y = 2 itself due to a horizontal asymptote here.

In interval notation, the answer would be (-\infty, 2) with the curved parenthesis to indicate "do not include y = 2 as part of the range".

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What is the value of f(3) when f(x) =4x+1
Makovka662 [10]

f(x) = 4x + 1 \\ f(3) = 4(3) + 1 \\  = 12 + 1 \\  = 13
3 0
3 years ago
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What is the value of x in the equation 6x +2y=48 when y=3
iren2701 [21]

Answer:

x=7

Step-by-step explanation:

6x +2y=48

Let y=3

6x+2(3) = 48

6x+6 = 48

Subtract 6 from each side

6x+6-6=48-6

6x= 42

Divide by 6

6x/6 = 42/6

x = 7

3 0
3 years ago
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For the equation 2(4x+10)=8x+k, which value of K will create an equation with infinitely many solutions?
saw5 [17]

Answer:

For given linear equation having infinite many solution the value of k is 20  .

Step-by-step explanation:

Given as :

The equation is 2 (4 x + 10) = 8 x + k

For infinite many solution , if the variable cancel out to zero then it will have infinite many solutions

<u>So, from given linear equation</u>

i.e 2 (4 x + 10) = 8 x + k

Or, 2 × 4 x + 2 × 10 = 8 x + k

Or, 8 x + 2 × 10 = 8 x + k

Or, 8 x + 20 = 8 x + k

Or, k + (8 x - 8 x) = 20

Or, k + 0 = 20

∴   k = 20

So, The vale of k  = 20

Hence, For given linear equation having infinite many solution the value of k is 20  . Answer

3 0
3 years ago
FREE 30 POINTS <br> Answer this question https://brainly.com/question/16063163
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Answer:

ok i answer

Step-by-step explanation:

yes

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3 years ago
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Find the area of a rectangle that has the length of 2x-3 and the width of x .Someone painted an interior area of the rectangle a
Svet_ta [14]

Answer:

The area that was not painted is (2x^{2}-6x+6)\ units^{2}

Step-by-step explanation:

step 1

Find the area of the rectangle

we know that

The area of a rectangle is equal to

A=LW

In this problem we have

L=2x-3

W=x

substitute

A=(2x-3)x\\A=(2x^{2}-3x)\ units^{2}

step 2

Find the area that was painted

A=(3)(x-2)\\A=(3x-6)\ units^{2}

step 3

Find the area that was not painted

Subtract the area that was painted from the total area of rectangle

so

A=(2x^{2}-3x)-(3x-6)=(2x^{2}-6x+6)\ units^{2}

8 0
3 years ago
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