Let's assume
Raj's age is x years
Zia's age is y years
we are given
Raj is three years older than zia
so, we get

now, we can solve for y

the sum of the squares of their ages is 369
so, we get

now, we can plug back y

now, we can solve for x





Since, age can not be negative
so, we will only consider positive

now, we can find y-value


So,
Raj's age is 15 years
Zia's age is 12 years...........Answer
Answer:
<h3>
A = ²⁵/₄x² + ⁷⁵/₂x + 50</h3>
Step-by-step explanation:
L = ⁵/₂x + 10
W = ⁵/₂x + 5
A = L•W
A = (⁵/₂x + 10)(⁵/₂x + 5)
A = ⁵/₂x•⁵/₂x + ⁵/₂x•5 + 10•⁵/₂x + 10•5
A = ²⁵/₄x² + ²⁵/₂x + ⁵⁰/₂x + 50
A = ²⁵/₄x² + ⁷⁵/₂x + 50
Or if yoy mean:
L = 5/(2x) + 10
W = 5/(2x) + 5
A = [5/(2x) + 10][5/(2x) + 5] = 25/(4x²) + 75/(2x) + 50