All categories

3 years ago

The same honey is sold in two different size jars.

Mathematics

1 answer:

labwork [276]3 years ago

3 0

Answer:

Large Jar:

510/439= 1.16p per 1g of honey

Small Jar:

380/312= 1.21p per 1g of honey

Therefore the Small Jar is best value for amount of honey per penny

Please Mark as Brainliest!

You might be interested in

Find the perimeter of the figure. AND I'LL MAKE YOU THE BRAINIEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

abruzzese [7]

9514 1404 393

Answer:

97 cm

Step-by-step explanation:

The perimeter is the sum of the side lengths. Starting from the upper left corner and working clockwise, the side lengths are ...

10 +3 +33 +15 +33 +3 = 25+2(36) = 97 . . . cm

The perimeter of the figure is 97 cm.

6 0

3 years ago

Crew b earns $315 after 3 hours, $525 after 5 hours, and $735 after 7 hours of work. Explain whether or not Crew b's data show a

Westkost [7]

Answer:

it in creases by 110 every hour

8 0

3 years ago

Read 2 more answers

Will give brainlst!! Have a amazing day :) Pls help

Nesterboy [21]

Answer:

Sorted Data Set: 2, 10, 12, 13, 14, 15, 17, 18, 18, 20, 21

Mean (Average) 14.545454545455

Median 15

Range 19

Mode 18, appeared 2 times

Geometric Mean 12.803503609558

Largest 21

Smallest 2

Sum 160

Count 11

First Quartile Q1 = 12

Second Quartile Q2 = 15

Third Quartile Q3 = 18

Interquartile Range IQR = 6

8 0

3 years ago

Thom worked 20 hours last week at the sporting-goods store and earned

Ilia_Sergeevich [38]

Answer:

He must work additional 8 hours.

Step-by-step explanation:

Because 1550.00/20=7.75

217.00/7.75=28

28-20=8

So,an additional of 8 hours

6 0

4 years ago

At a high school, students can choose between three art electives, four history electives, and five computer electives. Each stu

V125BC [204]

Answer:

$\frac{^3C_1\times ^4C_1}{^{12}C_2}$

Step-by-step explanation:

Given,

Art electives = 3,

History electives = 4,

Computer electives = 5,

Total number of electives = 3 + 4 + 5 = 12,

Since, if a student chooses an art elective and a history elective,

So, the total combination of choosing an art elective and a history elective = $^3C_1\times ^4C_1$

Also, the total combination of choosing any 2 subjects out of 12 subjects = $^{12}C_2$

Hence, the probability that a student chooses an art elective and a history elective = $\frac{\text{Total combination of choosing an art elective and a history}}{\text{ Total combination of choosing any 2 subjects}}$

$=\frac{^3C_1\times ^4C_1}{^{12}C_2}$

Which is the required expression.

3 0

3 years ago

Read 2 more answers