Question

12+36÷ (6^2÷ 3^2)??????​

Answer 1

Given:

The expression is

$12+36\div(6^2\div 3^2)$

To find:

The value of the expression.

Solution:

BODMAS: Brackets, orders, division, multiplication, addition and subtraction.

We have,

$12+36\div(6^2\div 3^2)$

Using BODMAS, first solve the brackets.

$=12+36\div(36\div 9)$

$=12+36\div(4)$

Now, divide.

$=12+9$

Now, add.

$=21$

Therefore, the value of given expression is 21.