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lina2011 [118]
3 years ago
6

Does the point (3,9) satisfy the inequality y<_2x + 2? yes no Submit

Mathematics
2 answers:
Lorico [155]3 years ago
7 0
Yes because 3 is less than or equal to 20
Sladkaya [172]3 years ago
7 0
Answer: yes


Hope this helped have a great day
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3 cards are drawn from a standard deck without replacement. What is the probability that at least one of the cards drawn is a re
Rudik [331]

Answer: \dfrac{15}{17}

Step-by-step explanation:

Total number of cards in a deck = 52

Number of red cards = 26

Number of cards not red =

Number of ways to draw not red cards = ^{26}C_3

Total ways to draw 3 cards = ^{52}C_3

The probability that none of three cards are red = \dfrac{^{26}C_3}{^{52}C_3}

=\dfrac{\dfrac{26!}{3!(26-3)!}}{\dfrac{52!}{3!(52-3)!}}  [∵ ^nC_r=\dfrac{n!}{r!(n-r)!}]

=\dfrac{\dfrac{26\times25\times24\times23!}{(23)!}}{\dfrac{52\times51\times50\times49!}{3!(49)!}}=\dfrac{2}{17}

Now , the probability that at least one of the cards drawn is a red card = 1- Probability that none cards are red

=1-\dfrac{2}{17}=\dfrac{17-2}{17}=\dfrac{15}{17}

Hence, the required probability = \dfrac{15}{17}

6 0
3 years ago
How many times does 12 go into 10
egoroff_w [7]

cant go into 10 bec its more than 10

6 0
4 years ago
Write the income equation for a small business that
algol [13]

Answer:

in 4 years

Step-by-step explanation:

because you should find the 20% of 150

150×20=3000

3000÷100= 30

so 20% of 150 is 30

then you keep adding 30 to the results till you reach 300

7 0
4 years ago
Read 2 more answers
Need help please don't get it <br>For each set of triangles,find the length of the missing side
Mumz [18]
4/20 = x/20 +x
80 + 4x = 20x
80/16 = x
5 = x

that being said. Is that your name???
6 0
3 years ago
If n+1 integers are chosen from the set
baherus [9]

Answer:

Pigeonhole Principle

Step-by-step explanation:

From series {1,2......2n} ; we need to select 'n + 1' integers.

Even integers series from above series = {2,4,6..........2(n-1), 2n}

Odd integers series from above series = {1,3,5........2(n-2), 2n-1}

So, we can choose only n odd integers from the series. Hence, if we choose n+1 integers, atleast one of them have to be even integer.

  • Eg : n = 5, Series = (1,2,3,4,5,6,7,8,9,10}, Odd series = {1,3,5,7,9}, Even series = {2,4,6,8,10}. If we choose 5 +1 ie 6 integers, there must be one even integer, as there are only 5 total odd integers in series.
4 0
3 years ago
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