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Nataly_w [17]
3 years ago
9

Help plsss Show me the work plsss

Mathematics
1 answer:
velikii [3]3 years ago
5 0

Answer:

a) y = 6x - 3

b) 1/3y = 2x -1

The first thing you need to do is isolate (y) in the second equation

3 x (1/3y) = 3 x (2x - 1)

y =6x - 3

After isolating (y) in equation b they end up being the same.

Graphing:

In order to graph this, you have to make the first point at (0, -3) since this is the Y-intercept of the equation.

In order to graph the other points, you must move 6 units up and 1 unit to the right. Or vise versa If you need a visual I'll gladly link one.

You might be interested in
A rectangle has its base on the x axis and its upper two vertices on the parabola y = 9 − x2. (a) Draw a graph of this problem.
gtnhenbr [62]

Answer:

  • (a) see attached
  • (b) width: 2x; height: y = 9-x²
  • (c) A=2x(9-x²) . . . 0 ≤ x ≤ 3
  • (d) dA/dx = -6x² +18; x=±√3
  • (e) 12√3 units²

Step-by-step explanation:

(a) The attachment shows the graph of the parabola in blue. It also shows an inscribed rectangle in black.

(b) The upper right point of the rectangle is shown in the attachment as (x, y). The dimension y is the height of the rectangle. The x-dimension is half the width of the rectangle, which is symmetrical about the y-axis. Hence the width is 2x.

(c) As with any rectangle, the area is the product of length and width:

... A = (2x)(9 -x²) . . . . . the attachment shows a graph of this

... A = -2x³ +18x . . . . . expanded form suitable for differentiation

A suitable domain for A is where both x and A are non-negative: 0 ≤ x ≤ 3.

(d) The derivative of A with respect to x is ...

... A' = -6x² +18

This is defined everywhere, so the critical values will be where A' = 0.

... 0 = -6x² +18

... 3 = x² . . . . . . . divide by -6, add 3

... √3 = x . . . . . . . -√3 is also a solution, but is not in the domain of A

(e) The rectangle will have its largest area where x=√3. That area is ...

... A = 2x(9 -x²) = 2√3(9 -(√3)²) = 2√3(6)

... A = 12√3 . . . . square units . . . . ≈ 20.785 units²

7 0
3 years ago
X=1/16y^2 the directrix of the parabola is
yan [13]
To solve this problem you must apply the proccedure shown below:

 1. You have the following equation of a parabola, given in the problem above:

 x<span>=1/16y^2

 2. Then, based on the graph attached, you have:

 p=y^2/4x
 p=8^2/(4)(4)
 p=64/16
 p=4

 3. The directrix is:

 directrix=h-p
 directrix=0-4
 directrix=-4

 The answer is:-4</span>

3 0
3 years ago
I neeeeeed heeeeelp plz
geniusboy [140]
The answer for number 4: Temperature is an average of average heat. Heat is the average kinetic energy and thermal energy is kinetic energy.  

(I can't see the answer for number 10... it would be good if you told me the question)
8 0
3 years ago
Please help with number 3!! I can’t figure it out.
FrozenT [24]

Answer:

Gabe worked 65, Abe worked 62 and Babe worked 69.

Step-by-step explanation:

Let Gabe = x

Therefore, Abe worked: x-3 and Babe worked x+4

So,

x+(x-3)+(x+4)=196

3*x+1=196

3*x=195

x=65

Then,

x-3= 62

x+4=69


8 0
3 years ago
Given: 2x + 3y= 6. When xhas a value of zero, the y value is 2. true or false<br>​
SIZIF [17.4K]
The answer is going to be true
8 0
3 years ago
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