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Fittoniya [83]
3 years ago
11

Which value of a in the exponential function below would cause the function to stretch?

Mathematics
1 answer:
mote1985 [20]3 years ago
5 0

Answer:

a' > a

Step-by-step explanation:

f(x)=ae^{bx}

A larger value for a will stretch the exponential in the y direction. A larger value for b will stretch it in the x direction.

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Which points are on the perpendicular bisector of the given segment? Check all that apply. Please explain how you got your answe
ser-zykov [4K]
First, you have to find the equation of the perpendicular bisector of this given line. 
to do that, you need the slope of the perpendicular line and one point.
Step 1: find the slope of the given line segment. We have the two end points (10, 15) and (-20, 5), so the slope is m=(15-5)/(10-(-20))=1/3
the slope of the perpendicular line is the negative reciprocal of the slope of the given line, m=-3/1=-3 
step 2: find the middle point: x=(-20+10)/2=-5, y=(15+5)/2=10      (-5, 10)
so the equation of the perpendicular line in point-slope form is (y-10)=-3(x+5)

now plug in all the given coordinates to the equation to see which pair fits:
(-8, 19): 19-10=9, -3(-8+5)=9, so yes, (-8, 19) is on the perpendicular line. 

try the other pairs, you will find that (1,-8) and (-5, 10) fit the equation too. (-5,10) happens to be the midpoint. 

4 0
3 years ago
Read 2 more answers
In a bag of m&m's there are 5 brown 6 yellow 4 blue 3 green and 2 orange. What's the probability of getting 3 yellow m&m
olasank [31]
There are 5+6+4+3+2=20 m&m's in the bag.
Calculate in how many ways you can choose 3 m&m's from 20:
_{20} C _3=\frac{20!}{3!(20-3)!}=\frac{20!}{3! \times 17!}=\frac{17! \times 18 \times 19 \times 20}{6 \times 17!}=\frac{18 \times 19 \times 20}{6}=3 \times 19 \times 20= \\
=1140

There are 6 yellow m&m's.
Calculate in how many ways you can choose 3 m&m's from 6:
_6 C _3 = \frac{6!}{3!(6-3)!}=\frac{6!}{3! \times 3!}=\frac{3! \times 4 \times 5 \times 6}{3! \times 6}=\frac{4 \times 5 \times 6}{6}=4 \times 5=20

The probability is the number of ways of choosing 3 m&m's from 6 m&m's divided by the number of ways of choosing 3 m&m's from 20 m&m's.
P=
\frac{20}{1140}=\frac{20 \div 20}{1140 \div 20}=\frac{1}{57}

The probability is 1/57.
4 0
3 years ago
9 packages of grape cost $24 how many packages of grapes can you buy for $8
Leto [7]
Ok. First you have to find the unit rate. Since you can buy 9 packages of grapes for $24, then you can get 1 grape package for $2.6667. If you have $8, you can buy 3 packages of grapes.
8 0
3 years ago
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Which situation CANNOT be represented by this equation? 3x+4=19
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3 0
3 years ago
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A jewelry store marks up the price of its jewelry up 50%. What will be the selling price of an item that the store purchased for
snow_tiger [21]

Answer: $142.5

Step-by-step explanation: If the price is being marked up by 50%, you take 50% or half of the original price of $95, which is 47.5, and add it to your original price.

95 + 47.5 = 142.5

3 0
3 years ago
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