The tangent vector to r(<em>t</em>) at any <em>t</em> in the domain is
At <em>t</em> = π/6, the tanget vector is
To get the unit tangent, normalize this vector by dividing it by its magnitude:
So the unit tangent at the given point is
Fill in the steps to solve the log log base x of (2x)^3=6
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To answer your question, it is shown in the image below
