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My name is Ann [436]
3 years ago
14

I really need help with distributive property

Mathematics
2 answers:
Strike441 [17]3 years ago
8 0

A quick explanation of distributive property:

Distributive property happens when multiple numbers are on the inside of parenthesis. There is a number on the outside that needs to be multiplied to both of the numbers on the inside of the parenthesis.

Distributive property is used because according to PEMDAS (the order in which you need to do operations in a multi-step equation) You need to do the problem on the INSIDE of the parenthesis first, because that's what the P in PEMDAS stands for. However, you cannot always do the operation on the inside of the parenthesis first. This normally happens because instead of having two numbers inside of the parenthesis, you have  at least one variable (letter that can be any number).

An example is this: (4 + 6) 3. This equation needs to follow PEMDAS, and you need to add the numbers inside the parenthesis first, before you multiply them by the number on the outside. However, if you distributed the 3 by multiplying it to both of the numbers inside the parenthesis BEFORE you added them together, you would get the same answer.  6 + 4 = 10 and 10 x 3 is thirty. 6 x 3 = 18 and 4 x 3 = 12. 12 + 18 = 30. However you shouldn't use distributive property unless you have an equation like this:

(x + 6) 3. Now you can't add x and 6 together, because x is a variable, and variables cannot be added to numbers, but we can use distributive property to multiply to both x and 6. then the equation is:  3x + 18.

docker41 [41]3 years ago
6 0

Answer:

To “distribute” means to divide something or give a share or part of something. According to the distributive property, multiplying the sum of two or more addends by a number will give the same result as multiplying each addend individually by the number and then adding the products together.

Step-by-step explanation:

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marusya05 [52]

Answer:

Yes, correct

Step-by-step explanation:

Hope that helppppps

7 0
3 years ago
Suppose that x and y are both differentiable functions of t and are related by the given equation. Use implicit differentiation
stepan [7]

Answer:

Let z = f(x, y) where f(x, y) =0 then the implicit function is

\frac{dy}{dx} =\frac{-δ f/ δ x }{δ f/δ y }

Example:- \frac{dy}{dx}  = \frac{-(y+2x)}{(x+2y)}

Step-by-step explanation:

<u>Partial differentiation</u>:-

  • Let Z = f(x ,y) be a function of two variables x and y. Then

\lim_{x \to 0} \frac{f(x+dx,y)-f(x,y)}{dx}    Exists , is said to be partial derivative or Partial differentiational co-efficient of Z or f(x, y)with respective to x.

It is denoted by δ z / δ x or δ f / δ x

  • Let Z = f(x ,y) be a function of two variables x and y. Then

\lim_{x \to 0} \frac{f(x,y+dy)-f(x,y)}{dy}    Exists , is said to be partial derivative or Partial differentiational co-efficient of Z or f(x, y)with respective to y

It is denoted by δ z / δ y or δ f / δ y

<u>Implicit function</u>:-

Let z = f(x, y) where f(x, y) =0 then the implicit function is

\frac{dy}{dx} =\frac{-δ f/ δ x }{δ f/δ y }

The total differential co-efficient

d z = δ z/δ x +  \frac{dy}{dx} δ z/δ y

<u>Implicit differentiation process</u>

  • differentiate both sides of the equation with respective to 'x'
  • move all d y/dx terms to the left side, and all other terms to the right side
  • factor out d y / dx from the left side
  • Solve for d y/dx , by dividing

Example :  x^2 + x y +y^2 =1

solution:-

differentiate both sides of the equation with respective to 'x'

2x + x \frac{dy}{dx} + y (1) + 2y\frac{dy}{dx} = 0

move all d y/dx terms to the left side, and all other terms to the right side

x \frac{dy}{dx}  + 2y\frac{dy}{dx} =  - (y+2x)

Taking common d y/dx

\frac{dy}{dx} (x+2y) = -(y+2x)

\frac{dy}{dx}  = \frac{-(y+2x)}{(x+2y)}

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Answer:

hftgftghgdfhgsdjthfdhrtfgredfgesdf

Step-by-step explanation:

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