For any quadrilateral to be a parallelogram
i) either both the pairs of opposite sides must be equal
ii) Both the pairs of opposite sides must be parallel
iii) Opposite pairs of angles must be equal
iv) Diagonals must bisect each other.
v) A pair of opposite sides must be parallel and equal
Here we are already given that AB || CD
So either we should be given that AD || BC
or we must be given that AB = CD
Here it is given AB = CD as an option.
So Option A) or the first option is the right answer that AB ≅CD is needed to prove ABCD is a parallelogram.
Answer:
1.333333... (only using (2,5) and (-4,-3)
Step-by-step explanation:
You do m=(y2-y1)/(x2-x1)
m=(-3-5)/(-4-2)=1.3333333...
First write down your equation. 2(y-3)=1.2-y. the distribute your 2. 2 times y is 2y and 2 times -3 is -6. now you have 2y-6=1.2-y. bring your y to the other side of the equation with the opposite sign and do the same with your 6. you have 2y+y=1.2+6. combine the like terms and constants. now you have 3y=7.2. divide bother sides of the equal by 3 to get y alone. 3y/3= 7.2/3. your answer is y=2.4.
Answer:
?
Step-by-step explanation:
?
Answer:
this is simply ok with help
