In radians:
To get 0, only one part of the multiplication needs to be zero for the whole thing to be zero. Thus we get 2 equations:
t=0, and cos(t)=0
for the first equation, it's pretty self-explanatory and sp we get 0 as one solution.
For the second equation, cos(pi/2) and cos(3pi/2) both equal 0 so both pi/2 and 3pi/2 are answers. Since there is no bound to this problem, the actual answer is:
(2Z+1)pi/2 and 0
(2Z+1) means all odd integers
Answer:
the linear graph man
please why ask ezzy questions
In triangle do pythogrean to find height 5 sq -3sq = 16 and sq rt of 16 is 4
So triangles are 1/2 bh 1/2 (3)4 = 6
One sale 5x5 one shape 5x4 one gape 3x5 plus two triangles
25+ 20+ 15 + 6+6= 72
6x3+3=21 there are 3 pieces of 6 inch ribbon which gives us the 6x3 and 1 piece of the 3 inch ribbon which makes us add 3
Answer:
2) 25%
Step-by-step explanation:
