Answer:
The equation is 4x + 5 = 2x + 6
Step-by-step explanation:
The solution is 
means x =
Let us put the coefficient of x in the left hand side = 4 and the coefficient of x in the right hand side = 2
∵ 4x - 2x = 2x
Now we need two numerical terms their difference is 1 like 5 and 6 or 6 and 7 or 7 and 8 or 8 and 9
Let us take 5 and 6
∵ 4x + 5 = 2x + 6
- Subtract 2x from both sides
∴ 2x + 5 = 6
- Subtract 5 from both sides
∴ 2x = 1
- Divide both sides by 2
∴ x =
∴ The solution is
The equation is 4x + 5 = 2x + 6
Solving for b, we have the equation A(b)=12*(b+9)/2 - we cancel out 12 and the 1/2 to get 6(b+9)=A(b) and get 6b+54=A(b). Subtract 54 from both sides to get 6b=A(b)-54 and divide both sides by 6 to get b=A(b)/6-9 = A
Answer: ∆V for r = 10.1 to 10ft
∆V = 40πft^3 = 125.7ft^3
Approximate the change in the volume of a sphere When r changes from 10 ft to 10.1 ft, ΔV=_________
[v(r)=4/3Ï€r^3].
Step-by-step explanation:
Volume of a sphere is given by;
V = 4/3πr^3
Where r is the radius.
Change in Volume with respect to change in radius of a sphere is given by;
dV/dr = 4πr^2
V'(r) = 4πr^2
V'(10) = 400π
V'(10.1) - V'(10) ~= 0.1(400π) = 40π
Therefore change in Volume from r = 10 to 10.1 is
= 40πft^3
Of by direct substitution
∆V = 4/3π(R^3 - r^3)
Where R = 10.1ft and r = 10ft
∆V = 4/3π(10.1^3 - 10^3)
∆V = 40.4π ~= 40πft^3
And for R = 30ft to r = 10.1ft
∆V = 4/3π(30^3 - 10.1^3)
∆V = 34626.3πft^3
150 is the answer to this question hope I help
Answer:
We have, volume of cone:
V = (1/3) x base area x height
= (1/3) x pi x radius^2 x height
= (1/3) x pi x 2^2 x 4
= 16.76 (mi3)
Option D is correct
Hope this helps!
:)
