I hope I’m not too late. Substitute x = 4y + 5y = 2
y = 2. Substitute this value into the first equation: x + -4 x 2 = -8. So the answer is (-8,2).
Option C
For each value of y, -2 is a solution of -21 = 6y - 9
<u>Solution:</u>
Given, equation is – 21 = 6y – 9
We have to find that whether given set of options can satisfy the above equation or not
Now, let us check one by one option
<em><u>Option A) </u></em>
Given option is -5
Let us substitute -5 in given equation
- 21 = 6(-5) – 9
- 21 = -30 – 9
- 21 = - 39
L.H.S ≠ R.H.S ⇒ not a solution
<em><u>Option B)</u></em>
Given option is 3
- 21 = 6(3) – 9
- 21 = 18 – 9
- 21 = 9
L.H.S ≠ R.H.S ⇒ not a solution
<em><u>Option C)</u></em>
Given option is -2
- 21 = 6(-2) – 9
- 21 = - 12 – 9
- 21 = - 21
L.H.S = R.H.S ⇒ yes a solution
<em><u>Option D)</u></em>
- 21 = 6(9) – 9
- 21 = 54 – 9
- 21 = 45
L.H.S ≠ R.H.S ⇒ not a solution
Hence, the solution for the given equation is – 2, so option c is correct
Answer:
definitely 4
Step-by-step explanation:
15/3 is 5 if u add 4 packets then I should he 20
Answer:
y = (x/(1-x))√(1-x²)
Step-by-step explanation:
The equation can be translated to rectangular coordinates by using the relationships between polar and rectangular coordinates:
x = r·cos(θ)
y = r·sin(θ)
x² +y² = r²
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r = sec(θ) -2cos(θ)
r·cos(θ) = 1 -2cos(θ)² . . . . . . . . multiply by cos(θ)
r²·r·cos(θ) = r² -2r²·cos(θ)² . . . multiply by r²
(x² +y²)x = x² +y² -2x² . . . . . . . substitute rectangular relations
x²(x +1) = y²(1 -x) . . . . . . . . . . . subtract xy²-x², factor
y² = x²(1 +x)/(1 -x) = x²(1 -x²)/(1 -x)² . . . . multiply by (1-x)/(1-x)
__
The attached graph shows the equivalence of the polar and rectangular forms.
For short you call this scientific notation.
FIRST
Count how many time you need to move the decimal over to make your single digit more then 1 and less then 10. So we will erase the 0's as we go along.
167000,000,000,000
So in this case we want to make the single digit 1.67 so it can be greater then 1 and less then 10
So now we see how many times we need to move the decimal and when you cant see the decimal just imagine it at the very end of the problem
167000,000,000,000
(For the mods out there I copied and pasted the bold number so i didn't have to take a while to retype the whole number. Thanks.)
SO NOW I get 14 because that's how many spots the decimal moved over.
Now since we need to right it in SN we need to write out this
X*10^X
The exponent X stands for how many times we moved the decimal over. I got 14 so we have that exponent
X*10^14
NOW We need to fiqure out X.... X was just the number we made greater then one and less then 0.
So thats 1.67
So we get
1.67*10^14
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