Write a polynomial in standard form that represents the area of the shaded region.

Mathematics

1 answer:

solmaris [256]3 years ago

6 0

(2x-9)(x+5)
Then expand
2x^2 +10x -9x -45
Simplify
2x^2 +x -45

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A circle has a diameter that starts

Kipish [7]

Find the distance between those points

diameter/2=radius

distance betwen (x1,y1) and (x2,y2) is
$D= \sqrt{(x2-x1)^2+(y2-y1)^2}$

given
(3,7) and (7,3)

$D= \sqrt{(7-3)^2+(3-7)^2}$
$D= \sqrt{(4)^2+(-4)^2}$
$D= \sqrt{16+16}$
$D= \sqrt{32}$
D=4√2

diameter/2=(4√2)/2=2√2

radius is 2√2

8 0

3 years ago

Which is the graph of the cube root function f(x) = RootIndex 3 StartRoot x EndRoot?

lara [203]

Answer:

<h3>On a coordinate plane, a cube root function goes through (negative 8, negative 2), has an inflection point at (0, 0), and goes thorugh (8, 2).</h3>

Step-by-step explanation:

$f(x)=\sqrt[3]{x}\\\\f(-8)=\sqrt[3]{-8}=-2\to(-8,\ -2)\\\\f(0)=\sqrt[3]{0}=0\to(0,\ 0)\\\\f(8)=\sqrt[3]{8}=2\to(8,\ 2)\\\\\\\sqrt[3]{a}=b\iff b^3=a\\\\\text{Therefore:}\\\\\sqrt[3]{-8}=-2\ \text{because}\ (-2)^3=-8\\\sqrt[3]0=0\ \text{because}\ 0^3=0\\\sqrt[3]{8}=2\ \text{because}\ 2^3=8$