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azamat
3 years ago
13

parking garage a charge A charge $3 per hour for parking. parking garage B charges of a fee of $ 2 pkus $ 2 per hour for parking

​
Mathematics
2 answers:
I am Lyosha [343]3 years ago
7 0

you good itStep-by-step explanation:

Alisiya [41]3 years ago
3 0
This is correct jesoisuza
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HELPPPPPPPPPPPPPPPPPPP!!!
Zielflug [23.3K]

Answer:

x=-4

Step-by-step explanation:

(x+4) ^ (1/3) + (2x+8) ^ (1/3) = 0

Subtract (x+4) ^ (1/3) from each side

(x+4) ^ (1/3) - (x+4) ^ (1/3)+ (2x+8) ^ (1/3) = -(x+4) ^ (1/3)

(2x+8) ^ (1/3) = -(x+4) ^ (1/3)

Cube each side

(2x+8) ^ (1/3) ^3= -(x+4) ^ (1/3)^3

2x+8 = -(x+4)

Distribute the negative sign

2x+8 = -x -4

Add x to each side

2x+8 +x =-x+x-4

3x+8 = -4

Subtract 8 from each side

3x+8-8 =-4-8

3x =-12

Divide by 3

3x/3 = -12/3

x = -4

8 0
3 years ago
Read 2 more answers
The driveway measuring 280 ft.² is to be paved john has an apprentice working for him and divide the child between the two of th
Furkat [3]

Answer:

Step-by-step explanation:

It would be 40

7 0
3 years ago
Law of sines: How many distinct triangles can be formed for which m∠A = 75°, a = 2, and b = 3? No triangles can be formed. One t
Vinvika [58]

We have been given angle A as 75 degrees and sides a = 2 and b = 3.

Using Sine rule, we can set up:

\frac{Sin(A)}{a}=\frac{Sin(B)}{b}

Upon substituting the given values of angle A, and sides a and b, we get:

\frac{Sin(75)}{2}=\frac{Sin(B)}{3}

Upon solving this equation for B, we get:

\Rightarrow 3Sin(75)=2Sin(B)\\  \Rightarrow Sin(B)=\frac{3Sin(75)}{2}\\  \Rightarrow Sin(B)=1.4488\\

Since we know that value of Sine cannot be more than 1. Hence there are no values possible for B.

Hence, the triangle is not possible. Therefore, first choice is correct.

7 0
3 years ago
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El 160% de T es igual a N que tanto porciento de N es el 60% de T
Dmitry_Shevchenko [17]

Answer:

sólo pasa por 100% nomás

8 0
3 years ago
Figure. <br> What are the pairs of congruent angles?
Anna35 [415]

∠QRS and ∠CDE are congruent.

∠RST and ∠DEB are congruent.

∠STQ and ∠EBC are congruent.

∠TQR and ∠BCD are congruent.


You can conclude the above angles are congruent because ∠R and ∠D has the same sign on their angle and so does ∠S and ∠E.

7 0
3 years ago
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