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Zarrin [17]
3 years ago
6

Eduphoria! - School

Mathematics
1 answer:
Masja [62]3 years ago
4 0

Answer: GACI

Step-by-step explanation:

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Which of these choices show a pair of equivalent expressions? A.7^5/7 and (√ 7)^5 B.6^7/2 and (√ 6)^7 C.(4√ 81)^7 and 81^7/4 D.5
OverLord2011 [107]
We will use the following law of indices (or 'index law') to check each pair of expression

x^{ \frac{m}{n}} = ( \sqrt[n]{x} )^{m}

With fractional power, the denominator is the root and the numerator is the power of the term. When the denominator is 2, we usually only write the normal square symbol (√). Denominator other than 2, we usually write the value of the root, for example, the cubic root ∛

Option A - Incorrect
7^{ \frac{5}{7}} should equal to ( \sqrt[7]{7} )^{5}

Option B - Correct
6^{ \frac{7}{2} } does equal to ( \sqrt{6}) ^{7}

Option C - Incorrect
4( \sqrt{81} )^{7} should equal to (4)( 81^{ \frac{7}{2} } )

Option D - Incorrect
5^{ \frac{2}{3} } should equal to ( \sqrt[3]{5} )^{2}
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Write the equivalent expression for 6x + 5y + 7x
Oksana_A [137]
I'm pretty sure it is d, you are combining the terms which is the same thing.
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URGENT PLEASE HELP WILL GIVE BRAINLIEST TO CORRECT ANSWER ABC factory brought a pile of coal. If the factory burns 1500 kilogram
wolverine [178]

Solving a system of equations, we will see that there are 6000 kg of coal on the pile.

<h3>How many kilograms of coal are in the pile of coal?</h3>

Let's say that there are N kilograms of coal, and it is planned to burn it totally in D days, these are our variables.

We know that:

  • If the factory burns 1500 kilograms per day, it will finish burning the coal one day ahead of planned.
  • If it burns 1000 kilograms per day, it will take an additional day than planned.

Then we can write the system of equations:

(1500)*(D - 1) = N

(1000)*(D + 1) = N

Because N is already isolated in both sides, we can write this as:

(1500)*(D - 1) = N = (1000)*(D + 1)

Then we can solve for D:

(1500)*(D - 1) =  (1000)*(D + 1)

1500*D - 1500 = 1000*D + 1000

500*D = 2500

D = 2500/500 = 5

Now that we know the value of D, we can find N by replacing it in one of the two equations:

(1500)*(D - 1) = N

(1500)*(5 - 1) = N

(1500)*4= N = 6000

This means that there are 6000 kilograms of coal on the pile.

If you want to learn more about systems of equations:

brainly.com/question/13729904

#SPJ1

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