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Ede4ka [16]
2 years ago
11

Select the correct answer. robin randomly selects a number between 1 and 20. what is the probability that the number selected is

the square of a natural number? a. b. c. d. e.
Mathematics
1 answer:
Vlada [557]2 years ago
8 0

The probability that the number selected is the square of a natural number will be  \frac{1}{5}.

<h3 /><h3>What is probability?</h3>

Probability means possibility. It deals with the occurrence of a random event. The value of probability can only be from 0 to 1.

Its basic meaning is something is likely to happen. It is the ratio of the favorable event to the total number of events.

P is the probability

F(E) is the favorable event

T(E)is the total event

The probability is found as;

\rm P = \frac{F(E)}{T(E)} \\\\ \rm P = \frac{4}{20)} \\\\ \rm P = \frac{1}{5}

Hence the probability that the number selected is the square of a natural number will be  \frac{1}{5}.

To learn more about the probability link is given below.

brainly.com/question/795909

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Novay_Z [31]

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Step-by-step explanation:

Given the following expression shown in the picture:

\frac{7}{3-\sqrt{2} }

You need to use a process called "Ratinalization".

By definition, using Rationalization you can rewrite the expression in its simplest form so there is not Radicals in its denominator.

Then, in order to simplify the expression, you can follow the following steps:

<em>Step 1</em>. You need to multiply the numerator and the denominator of the fraction by  3+\sqrt{2}, which is the conjugate of the denominator  3-\sqrt{2}.

<em>Step 2</em>. Then you must apply the Distributive property in the numerator.

<em>Step 3</em>. You must apply the following property in the denominator:  (a+b)(a-b) = a^2 - b^2

Therefore, applying the procedure shown above, you get:

=\frac{(7)(3+\sqrt{2})}{(3-\sqrt{2})(3+\sqrt{2})}=\frac{21+7\sqrt{2}}{3^2-(\sqrt{2})^2}=\frac{21+7\sqrt{2}}{9-2}=\frac{21+7\sqrt{2}}{7}

<em>Step 4</em>.  You can observe that the expression can be simplified even more. Since:

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You get:

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