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podryga [215]
3 years ago
12

Me pueden ayudar en esto por favor​

Mathematics
1 answer:
Whitepunk [10]3 years ago
3 0

Answer:

2cm: 6.28

4cm: 12.56

6cm: 18.84

8cm: 25.12

10cm: 31.4

12cm: 37.68

Step-by-step explanation:

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-5x+2y=6<br> -x+2y=-2 <br> what is the solution to the system of equations?
dybincka [34]

Step-by-step explanation:

- 5x + 2y = 6 \\ - x + 2y =  - 2 \\  \\  - 5x + 2y - ( - x + 2y) = 6 - ( - 2) \\  - 5x + 2y + x - 2y = 6 + 2 \\  - 4x = 8 \\  \frac{ - 4x}{ - 4}  =  \frac{8}{ - 4 }  \\ x =  (- 2) \\  \\  -5x + 2y =  6 \\  - 5 \times  - 2 + 2y = 6 \\ 10 + 2y = 6 \\ 2y = 6 - 10 \\ 2y =  - 4 \\  \frac{2y}{2}  =  \frac{ - 4}{2}  \\ y =  - 2 \\  now \: lets \: see \: whether \\ this \: equation \: is \: correct. \\  - x + 2y = -  2 \\ -   ( - 2) + 2 \times  - 2 = -  2 \\ 2 + 2  \times   - 2 =  - 2 \\ 2 - 4 =  - 2 \\  - 2 =  - 2 \\ yes \: this \: equation \: is \\ correct.

7 0
3 years ago
Suzanne owns a small business that employs 555 other people. Suzanne makes \$100{,}000$100,000dollar sign, 100, comma, 000 per y
zalisa [80]

Answer:

16

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
I know that real numbers consist of the natural or counting numbers, whole numbers, integers, rational numbers and irrational nu
ra1l [238]

The imaginary unit i belongs to the set of complex numbers, denoted by \mathbb C. These numbers take the form a+bi, where a,b are any real numbers.

The set of real numbers, \mathbb R, is a subset of \mathbb C, where each number in \mathbb R can be obtained by taking b=0 and letting a be any real number.

But any number in \mathbb C with non-zero imaginary part is not a real number. This includes i.

  • "is it possible that i can use an imaginary number for a real number"

I'm not sure what you mean by this part of your question. It is possible to represent any real number as a complex number, but not a purely imaginary one. All real numbers are complex, but not all complex numbers are real. For example, 2 is real and complex because 2=2+0i.

There are some operations that you can carry out on purely imaginary numbers to get a purely real number. A famous example is raising i to the i-th power. Since i=e^{i\pi/2}, we have

i^i=\left(e^{i\pi/2}\right)^i=e^{i^2\pi/2}=e^{-\pi/2}\approx0.2079

3 0
3 years ago
Someone help me with this show work
kakasveta [241]
The equation has three factors and equals zero
One of the factors must be zero.
Either 3x = 0 which means x = 0
or x - 4 = 0 which means x = 4
or 3x + 5 = 0 which means 3x = -5 so x = -5/3

The answer is C

E cannot be correct in this question as you are asked to “solve” and not just pick a correct option
3 0
3 years ago
Calculate the surface area of the figure below.
valentinak56 [21]

Answer:

a. 1,275.49 m²

Step-by-step explanation:

SA = 2πr² + 2πrh

SA = 2π(7)² + 2π(7)(22)

SA = 98π + 308π

SA = 406π

SA ≈ 1,275.49 m²

8 0
3 years ago
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