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strojnjashka [21]
3 years ago
7

The graph below shows the solution to which system of inequalities? 10- TO 10 -10

Mathematics
1 answer:
Alona [7]3 years ago
4 0
Neurehjrhreidnnfejfueiendnd
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here are the ingredients for making fish pie for 5 people. 180g flour,240g fish,80g butter,4 eggs, 180ml milk . Lan makes a fis
kvasek [131]
5p = 80b
3(5p) = (80b)3
15p = 240b

Lan need 240g of butter to make fish pie for 15 people.
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1/3 of a cup of flour is used to make 6 cinnamon rolls. How much fliur is needed to make 1 cinnamon roll?
Debora [2.8K]
I hope this helps you

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4 years ago
WHY is the work they give us online harder than the work we get at school? SOMEBODY PLEASE HELP :(
Dmitry_Shevchenko [17]

Answer:

First question

Circle A:

Radius:2.5 Diameter: 5 Circumference:15.71

Circle B:

Radius:12 Diameter:24 Circumference:75.4

Circle C:

Radius:32 Diameter:64 Circumference:201.06

Circle D:

Radius:42 Diameter:84 Circumference:263.89

Second one:

without Pi

1:81.68

2:37.7

3:263.89

with pi

1:26π

2:12π

3:84π

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8 0
4 years ago
Y=-x^2+6x-4<br> Find the Axis of Symmetry and the Vertex, Also solve the whole equation.
Inessa [10]

Answer:

1. <em>Axis of symmetry</em>: x = 3

2. <em>Vertex:</em> (3,5)

3. <em>Solution of the equation</em>:

<u />

  • x-intercepts:

               (3-\sqrt{5},0) \\\\(3+\sqrt{5},0)

  • y-intercept: (0, -4)

Explanation:

<u>1. Equation:</u>

    y=-x^2+6x-4

<u>2. </u><em><u>Axis of symmetry:</u></em>

That is the equation of a parabola, whose standard form is:

                 y=ax^2+bx+c

Where:    

                 a=-1;b=6;c=-4

The axis of symmetry is the vertical line with equation:

               x=-b/2a

Substitute  a=-1,\text{ and }b=6

          x=-6/[(2)(-1)]=-6/(-2)=3

Thus, the axis of symmetry is:

            x=3

<em><u>3. Vertex</u></em>

<em><u /></em>

The x-coordinate of the vertex is equal to the axys of symmetry, i.e x = 3.

To find the y-xoordinate, substitute this value of x into the equation for y:

               y=-x^2+6x-4\\\\y=-(3)^2+6(3)-4=-9+18-4=5

Therefore, the vertex is (3, 5)

<u>4. Find the x-intercepts</u>

The x-intercepts are the roots of the equation, which are the points wher y = 0.

        y=-x^2+6x-4=0

Use the quadratic equation:

       x=\frac{-b\pm \sqrt{b^2-4ac} }{2a} \\\\x=\frac{-6\pm\sqrt{(-6)^2-4(-1)(-4)} }{2(-1)}\\\\x_1=3-\sqrt{5} \\\\x_2=3+\sqrt{5}

<u>5. Find the y-intercept</u>

<u />

The y-intercet is the value of y when x=0:

         y=-x^2+6x-4\\\\y=-(0)^2+6(0)-4=-4

7 0
4 years ago
Solve the following by first clearing the fractions.<br><br> 1/6x+1/2=1/2x+1/2
levacccp [35]

Answer:

.166x + .5 = .5x +.5

Step-by-step explanation:

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3 years ago
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