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3 years ago

What's 1+9 pls helpppppppp

Mathematics

1 answer:

skad [1K]3 years ago

7 0

Your answer would be 10

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Help me asap

sasho [114]

Answer:

6p =120

Step-by-step explanation:

well the p's are very close together in a sense that we are going to multiply instead of add because they the p's would have space in between

6 * 20 = 120

so p= 20

6 0

3 years ago

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HELP ASAP : Find the largest value of n such that 5x^2+nx+48 can be factored as the product of two linear factors with integer c

Anna71 [15]

Answer:

$n=241$

Step-by-step explanation:

We are given

$5x^2+nx+48$

Let's assume it can be factored as

$5x^2+nx+48=(5x-s)(x-r)$

now, we can multiply right side

and then we can compare it

$5x^2+nx+48=5x^2-5rx-sx+rs$

$5x^2+nx+48=5x^2-(5r+s)x+rs$

now, we can compare coefficients

$rs=48$

$5r+s=-n$

$n=-(5r+s)$

now, we can find all possible factors of 48

and then we can assume possible prime factors of 48

$48=-+(1\times 48)$

$48=-+(2\times 24)$

$48=-+(3\times 16)$

$48=-+(4\times 12)$

$48=-+(6\times 8)$

Since, we have to find the largest value of n

So, we will get consider larger value of r because of 5r

and because n is negative of 5r+s

so, we will both n and r as negative

So, we can assume

r=-48 and s=-1

so, we get

$n=-(5\times -48-1)$

$n=241$

7 0

3 years ago

Which model best fits the set of data shown on this graph?

Blizzard [7]

Answer:

Step-by-step explanation:

Quadratic model is shaped like a "U", or a parabola

Quartic model is shaped like a "W", highest degree is 4 (x^4).

Linear model is a line.

Cubic model is x^3, shaped like a curvy snake.

Looking at the graph, it <em>clearly</em> shows a line. So, linear model is the answer.

C is the correct answer.

4 0

3 years ago

Questions in picture

zmey [24]

Answer:

z-test

hu=50

Step-by-step explanation:

7 0

3 years ago

Kyle has a total of 16 coins in his pocket. All the coins are nickels or quarters, and they have a total value of $2.20. How man

kupik [55]

Answer:

9 nickels

Step-by-step explanation:

6 0

3 years ago

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