A line passes through the points (3, –1) and (5, 4). What is the slope of the line?

Mathematics

2 answers:

forsale [732]3 years ago

6 0

Answer:

D) 5/2

Step-by-step explanation:

(3, –1) and (5, 4)

Slope:

m=(y2-y1)/(x2-x1)

m=(4 + 1)/(5 - 3)

m= 5/2

Inessa [10]3 years ago

4 0

Answer:

5/2

Step-by-step explanation:

To find the slope, we can use the slope formula

m= (y2-y1)/(x2-x1)

= (4 - -1)/(5 - 3)

= (4+1)/(5-3)

= 5/2

You might be interested in

For his long distance phone service, Boris pays a $7 monthly fee plus 7 cents per minute. Last month, Boris's long distance bill

Allushta [10]

$16.38 - $7 = 9.38 7 cents x 134 = 9.38 so the answer would be 134 minutes or 2h 14 min

6 0

3 years ago

10. In APQR, right-angled at Q, PR+QR = 25 cm and PQ = 5 cm. Determine the values of

Anettt [7]

<h2><em>Given PR + QR = 25 , PQ = 5 </em></h2><h2><em>PR be x. and QR = 25 - x </em></h2><h2><em> </em></h2><h2><em>Pythagoras theorem ,PR2 = PQ2 + QR2 </em></h2><h2><em> </em></h2><h2><em>x2 = (5)2 + (25 - x)2 </em></h2><h2><em> </em></h2><h2><em>x2 = 25 + 625 + x2 - 50x </em></h2><h2><em>50x = 650 </em></h2><h2><em>x = 13 </em></h2><h2><em> </em></h2><h2><em> </em></h2><h2><em> PR = 13 cm </em></h2><h2><em>QR = (25 - 13) cm = 12 cm </em></h2><h2><em> </em></h2><h2><em>sin P = QR/PR = 12/13 </em></h2><h2><em> </em></h2><h2><em>cos P = PQ/PR = 5/13 </em></h2><h2><em> </em></h2><h2><em>tan P = QR/PQ = 12/5 </em></h2><h2><em /></h2><h2><em>HOPE IT HELPS (◕‿◕✿)</em></h2>

6 0

3 years ago

Hey Heyy njknckslje whas good people

MariettaO [177]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

6-7 Please help BRAINLEST!

elena55 [62]

Answer: