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3 years ago

If mZOKL = 80°, then what is mZHKJ? С E А4 N H K M

Mathematics

1 answer:

Nookie1986 [14]3 years ago

5 0

MOKL and mHKJ are vertical angles, so they’re congruent
so mHKJ is also 80°

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Which x-values make the ordered pair (x, -6) a solution of the system of inequalities represented by the graph below?

BigorU [14]

Answer:

C) -4 ≤ x < 0

Step-by-step explanation:

the x-values make the ordered pair (x,-6). the solution of inequalities represented by the graph gives the solution -4 ≤ x < 0

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3 years ago

I really need help plz help me ✌️️

OLEGan [10]

The answer is 7/4. Hope this helps! :)

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4 years ago

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There is a string of red and blue lights strung around a window. The red lights blink every 3 seconds , and the blue lights blin

Eddi Din [679]

Answer:

they will blink 4 times at the same time in one minute

Step-by-step explanation:

you have to find the least common multiple of 5 and 3

LCM of 5,3 = 15

So, the two lights will blink together every 15 seconds.

No.of times blinking together in one minute = 60/15 = 4

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3 years ago

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ASK YOUR TEACHER An article reported that for a sample of 42 kitchens with gas cooking appliances monitored during a one-week pe

xxMikexx [17]

Answer:

$654.16-2.02\frac{165.23}{\sqrt{42}}=602.66$

$654.16+2.02\frac{165.23}{\sqrt{42}}=705.66$

So on this case the 95% confidence interval would be given by (602.66;705.66)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=654.16$ represent the sample mean

$\mu$ population mean (variable of interest)

s=165.23 represent the sample standard deviation

n=42 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=42-1=41$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,41)".And we see that $t_{\alpha/2}=2.02$

Now we have everything in order to replace into formula (1):

$654.16-2.02\frac{165.23}{\sqrt{42}}=602.66$

$654.16+2.02\frac{165.23}{\sqrt{42}}=705.66$

So on this case the 95% confidence interval would be given by (602.66;705.66)

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4 years ago

Susie is making fruit baskets for her school fundraiser she has 28 bananas and 21 apples what are the most food baskets that you

kondaur [170]

7 is the most

Hope this helped :)

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3 years ago