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ale4655 [162]
3 years ago
14

How to i find the lowest terms of a ratio 12 minutes to 3 hrs ?​

Mathematics
2 answers:
Natasha2012 [34]3 years ago
5 0
The answer is to this question is 75
mihalych1998 [28]3 years ago
3 0

Answer:75 minutes. Pls brainless..

Step-by-step explanation:

In order to express a ratio in the simplest form, we find the HCF of the terms ... 60/48 (divide both the numerator and denominator by 12 since, the h.c.f. of 60 ... (vi) 3 hours to 75 minutes.

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Rachel earned $85.25 for working 6 1 4 hours. How much does Rachel earn per hour?
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Answer:

Rachel earns per hour is $ 13.64 .

Step-by-step explanation:

As given

Rachel earned $85.25 for working 6 \frac{1}{4} hours.

i.e

Rachel earned $85.25 for working \frac{25}{4} hours.

Now calculate earning of Rachel for 1 hour .

Rachel\ earning\ for\ one\ hour = \frac{Total\ earning}{Total\ time}

Rachel\ earning\ for\ one\ hour = \frac{85.25}{\frac{25}{4}}

Rachel\ earning\ for\ one\ hour = \frac{85.25\times 4}{25}

Rachel\ earning\ for\ one\ hour = \frac{341}{25}

Rachel\ earning\ for\ one\ hour = \$ 13.64

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3 years ago
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Step-by-step explanation:

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3 years ago
If ABF= (7x + 20), FBC=(2x - 5), and ABC= 159", find the value of x. x =
s2008m [1.1K]

Given :

∠ABF = ( 7x + 20 )°

∠FBC=(2x - 5)°

∠ABC= 159°

To Find :

The value of x .

Solution :

Assuming B the center of a circle .

So , all three given angles must be added to 360° .

(7x+20)+(2x-5)+159=360\\\\9x+15+159=360\\\\x=20.67

Therefore , the value of x is 20.67° .

Hence , this is the required solution .

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3 years ago
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Step-by-step explanation:

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In a geometric sequence, A1 = 0.3 and r=3.Find A12, to the nearest integer
soldi70 [24.7K]

Step-by-step explanation:

We have,

First terms of geometric sequence, a = 0.3

Common ratio, r = 3

It is required to find the 12th term of a GP. The formula of the nth term is given by :

T_n=ar^{n-1}

Here, n =12

So,

T_{12}=0.3\times 3^{12-1}\\\\T_{12}=0.3\times 3^{11}\\\\T_{12}=53144.1

or

T_{12}=53144

So, the 12th term of the GP is 53144.

8 0
4 years ago
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