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3 years ago

7

Ash is 4 years younger than Gary, and Oak is 5 times Gary's age. The sum of their three ages is 94. Find Gary's age. Show workin

g out. Thanks!!

1 answer:

tiny-mole [99]3 years ago

7 0

Answer:

Step-by-step explanation:

If Gary's age is 14 then

Ash is 4 years younger = 14 - 4 = 10

And Oak is 5 times Gary's age = 14 x 5 = 70

So total ages = 70 + 14 + 10 = 94

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gladu [14]

Answer:

The perimeter of triangle is 33 meters.

Step-by-step explanation:

Given that the triangle is Equivalent Triangle where all angles and sides are equal, so we can assume that:

7x - 17 = 4x - 5

7x - 4x = 17 - 5

3x = 12

x = 12 ÷ 3

x = 4

OR:

4x - 5 = 2x + 3

4x - 2x = 3 + 5

2x = 8

x = 8 ÷ 2

x = 4

Substitute x = 4 into all expressions:

7x - 17 = 7(4) - 17 = 11 meters

4x - 5 = 4(4) - 5 = 11 meters

2x + 3 = 2(4) + 3 = 11 meters

In order to find out the perimeters, you have to add up all the sides:

P = 11 + 11 + 11

P = 33 meters

3 0

3 years ago

Read 2 more answers

CERTAIN ANSWERS!!! Please assist me! I will award you brain crown! Thank you in advance:))

snow_tiger [21]

Answer:

See below.

Step-by-step explanation:

Statements: Reasons:

1) $\angle 2\cong\angle 3$ Given

2) $m\angle2=m\angle 3$ Definition of Congruence

3) $\angle 1\text{ and } \angle 2\text{ form a linear pair}$ Given

4) $\angle 1 \text{ and } \angle 2\text{ are supplementary}$ Supplement Theorem

5) $m\angle 1+m\angle 2=180^\circ$ Definition of Supplementary Angles

6) $m\angle 1+m\angle 3=180&^\circ$ Substitution

7) $\angle 1\text{ and } \angle 3 \text{ are supplementary}$ Definition of Supplementary

And we're done!

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4 years ago

You row upstream at a speed of 2 mi/h. You travel the same distance

Reika [66]

Answer:

3.5 m/hr

Step-by-step explanation:

2 + c = 5 -c c = speed of current

2 c = 3 c = current speed = 1.5 m/hr

your speed = 5 - 1.5 (or 2 + 1.5) = 3.5 m/hr

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2 years ago

Ayuda porfavor es urgente

san4es73 [151]

B for one and D for 2
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5 0

3 years ago

A thermometer is taken from a room where the temperature is 20◦C to the

lord [1]

Answer:

a) $T(2) = 8.265$ : at time t = 2 minutes the temperature will be 8.265 degress

b) $6 = T(3.55)$ : the temperature will be 6 degrees at time t = 3.55 minutes.

Step-by-step explanation:

When dealing with temperature changes, it's best to work with Newton's Law of Cooling.

$T(t) = T_s + Ce^{kt}$

here:

$T(t)$ : the temperature in the room.

$T_s$ : ambient (or outdoor) temperature (that always remains constant, in our case: $T_s = 5$ )

$C\,\text{and}\,k$ : are constants

Our conditions are provided:

1) $T(0) = 20$

2) $T(1) = 12$

using the first condition

$T(0) = 5 + Ce^{k(0)}\\20 = 5 + C(1)\\C = 15$

using the second condition:

$T(1) = 5 + Ce^{k(1)}\\12 = 5 + Ce^{k}\\e^k = \dfrac{7}{C}$

we can use our calculated value of C to find k

$e^k = \dfrac{7}{15}\\k = \ln{(\dfrac{7}{15})}\\k = -0.7621$

Finally we can put these constants back in the main equation:

$T(t) = T_s + Ce^{kt}$

$T(t) = 5 + 15e^{-0.7621t}$ or $T(t) = 5 + 15e^{\ln{(\frac{7}{15})t}$

a) Reading after one more minute?

so it's asking:

T(2) = ?

$T(2) = 5 + 15e^{\ln{(\frac{7}{15})(2)}}\\T(2) = \dfrac{124}{15} \approx 8.267$

Hence, after one more minute the temperature of the room will be 8.267 degrees

b) When will it be 6 degrees?

T(t) = 6?

$6 = 5 + 15e^{-0.7621t}\\\text{and solve for $t$}\\\\\dfrac{6-5}{15}=e^{\ln{(\frac{7}{15})}t}\\\ln{\left(\dfrac{1}{15}\right)} = \ln{\left(\dfrac{7}{15}\right)t}\\\ln{\left(\dfrac{1}{15}\right)} \div \ln{\left(\dfrac{7}{15}\right)} = t \approx 3.55\\$

Hence at t = 3.55 minutes the temperature of the room will be 6 degrees.

8 0

3 years ago