2/3(6c+4)-(8c-5)
1) Get rid of the negative signs
New equation (the ones in bold are the changes): 2/3(6c+4)+(-8c)+(5)
2) Use distributive property for the first part by multiplying 2/3*6c= 4c and 2/3*4= 2 2/3
New equation: 4c+2 2/3+ (-8c) + 5
3) Combine like terms: 4c+(-8c)= -4c and 2 2/3+5= 7 2/3
New and simplified equation: -4c+ 7 2/3
1. It is the product of a square, meaning it can be simplified to (x+10)(x+10) or (x+10)^2
(12x + 9y) + (-2y) - (4x - 3y)
= 12x + 9y - 2y - 4x + 3y
= 12x - 4x + 9y - 2y + 3y
= 8x + 10y
A) 8x + 10y
Answer:
y-coordinate = 0
Step-by-step explanation:
Consider the below diagram attached with this question.
Section formula:
If a point divides a line segment in m:n whose end points are
and
, then the coordinates of that point are
![(\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n})](https://tex.z-dn.net/?f=%28%5Cfrac%7Bmx_2%2Bnx_1%7D%7Bm%2Bn%7D%2C%5Cfrac%7Bmy_2%2Bny_1%7D%7Bm%2Bn%7D%29)
From the below graph it is clear that the coordinates of end points are J(1,-10) and K(7,2). A point divides the line JK is 5:1.
Using section formula, the coordinates of that point are
![(\frac{(5)(7)+(1)(1)}{5+1},\frac{(5)(2)+(1)(-10)}{5+1})](https://tex.z-dn.net/?f=%28%5Cfrac%7B%285%29%287%29%2B%281%29%281%29%7D%7B5%2B1%7D%2C%5Cfrac%7B%285%29%282%29%2B%281%29%28-10%29%7D%7B5%2B1%7D%29)
![(\frac{35+1}{6},\frac{10-10}{6})](https://tex.z-dn.net/?f=%28%5Cfrac%7B35%2B1%7D%7B6%7D%2C%5Cfrac%7B10-10%7D%7B6%7D%29)
![(\frac{36}{6},\frac{0}{6})](https://tex.z-dn.net/?f=%28%5Cfrac%7B36%7D%7B6%7D%2C%5Cfrac%7B0%7D%7B6%7D%29)
![(6,0)](https://tex.z-dn.net/?f=%286%2C0%29)
Therefore, the y-coordinate of the point that divides the directed line segment from J to k into a ratio of 5:1 is 0.
Answer:
0,-2,-8,-36
Step-by-step explanation: