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viktelen [127]
2 years ago
12

14.1-191 Is this the answer?

Mathematics
2 answers:
Ann [662]2 years ago
7 0
I don’t understand your question
enyata [817]2 years ago
4 0
I don’t know if this is what you’re asking but 14.1-191 = -176.9
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In a group of 60 students, 12 students take Algebra I, 18 students take Algebra II, and 8 students take both subjects. How many
vodomira [7]
Since 8 students take both, that leaves only 4 students who take Algebra I alone.
Likewise since 8 students take both, that leaves 10 who only take Algebra 2
So out of the 60, twenty two are taking either Alg I Alg Ii or both.

That leaves 38 people who are not taking either.
b. 38

You can set this up using a 2 circle venn diagram.  Just be sure to put the 8 who take both in first.

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3 years ago
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Suppose that the mean score of a class of 32 students was 74. the 19 male students in the class had a mean score of 70. what was
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How would you justify that triangle G'H'I' is congruent to MNO?
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1 year ago
According to a study conducted in one city, 35% of adults in the city have credit card debts more than $2.000. A simple random s
BabaBlast [244]

Answer:

Binomial; \mu p=87.5, \sigma p=7.542

Step-by-step explanation:

  • a distribution is said be a binomial distribution iff
  1. The probability of success of that event( let it be p) is same for every trial
  2. each trial should have 2 outcome : p or (1-p) i.e, success or failure only.
  3. there are fixed number of trials (n)
  4. the trials are independent
  • here, the trials are obviously independent ( because, one person's debt doesn't influence the other person's)
  • here n=250
  • the probability of success(0.35) is same for every trial

(35/100=0.35 is the required p here)

  • \mu_{p} =n*p=250*\frac{35}{100} =250*0.35=87.5

[since, the formula for \mu _{p} =n*p ]

  • \sigma _{p} =\sqrt{n*(p)*(1-p)} = \sqrt{250*0.35*(1-0.35)} = 7.542 ( approximately)

[since, the formula for [tex]\sigma _{p} =\sqrt{n*(p)*(1-p)}

  • therefore, it is Binomial; \mu p=87.5, \sigma p=7.542

4 0
3 years ago
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