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Makovka662 [10]
3 years ago
14

If tan x =1/2 find sin x 2

Mathematics
1 answer:
irina1246 [14]3 years ago
6 0

Answer:

t

=

26

∘

57

+

k

360

∘

Step-by-step explanation:

tan

t

=

1

2

Calculator and unit circle give 2 solutions for (0, 360) -->

t

=

26

∘

57

, and

t

=

180

+

26.57

=

206

∘

57

General answer:

t

=

26

∘

57

+

k

360

∘

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The mean and standard deviation when presenting results?
krek1111 [17]

Answer:

Standard deviation is a number used to tell how measurements for a group are spread out from the average (mean), or expected value. A low standard deviation means that most of the numbers are close to the average. A high standard deviation means that the numbers are more spread out.

Step-by-step explanation:

7 0
3 years ago
Zach is 4 years older than twice his sister maya’s age. maya is 5 years old. how old is zach?
SCORPION-xisa [38]
Zach is 14 bc...
-4 years older(+4) than twice (x2) Mayas age.
-Maya is 5
- the correct order is 5x2+4
-5x2=10, 10+4=14
4 0
3 years ago
Write these in standard form :
kotegsom [21]

8.23\cdot10^6=8.23\cdot1,000,000=8,230,000\\\\2.4\cdot10^5=2.4\cdot100,000=240,000

\text{The scientific notation:}\ a\cdot10^n\ (1\leq a < 10,\ n\in\mathbb{Z})\\\\4\underbrace{50000}_{\leftarrow5}=4.5\cdot10^5\\\\320=3.2\cdot100=3.2\cdot10^2\\\\0.\underbrace{0000006}_{7\rightarrow}73=6.73\cdot10^{-7}\\\\3\underbrace{2100000}_{\leftarrow7}=3.12\cdot10^7

7 0
3 years ago
Please help me with this will reward brainlest
larisa [96]

5.35 + 3.8 + 2 = 11.15 pounds in total

Answer

D. 11.15

6 0
3 years ago
Read 2 more answers
Find the solution r(t)r(t) of the differential equation with the given initial condition: r′(t)=⟨sin4t,sin7t,9t⟩,r(0)=⟨9,8,3⟩
Makovka662 [10]
\mathbf r'(t)=\langle\sin4t,\sin7t,9t\rangle
\implies\mathbf r(t)=\displaystyle\int\mathbf r'(t)\,\mathrm dt
\mathbf r(t)=\displaystyle\left\langle\int\sin4t\,\mathrm dt,\int\sin7t\,\mathrm dt,\int9t\,\mathrm dt\right\rangle
\mathbf r(t)=\left\langle-\dfrac14\cos4t+C_1,-\dfrac17\cos7t+C_2,-\dfrac92t^2+C_3\right\rangle

With \mathbf r(0)=\langle9,8,3\rangle, we have

\langle9,8,3\rangle=\left\langle-\dfrac14+C_1,-\dfrac17+C_2,C_3\right\rangle
\implies C_1=\dfrac{37}4,C_2=\dfrac{57}7,C_3=8
\implies\mathbf r(t)=\left\langle-\dfrac14\cos4t+\dfrac{37}4,-\dfrac17\cos7t+\dfrac{57}7,-\dfrac92t^2+8\right\rangle
6 0
3 years ago
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