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denpristay [2]
2 years ago
13

Percents can be expressed as fractions and decimals. A percent means “out of 100,” so we can express 40% as the fraction 40⁄100.

We can simplify this fraction to2⁄5 by dividing by the greatest common factor, 20.
We can also express a percent as a decimal. Percents show a part out of a hundred, or hundredths, so you can divide the percent by 100 to find the decimal. 40 divided by 100 equals 40 hundredths, or .4. You can also divide the numerator by the denominator in the simplified fraction, 2⁄5, to find the equivalent decimal.


These values are all equivalent.

75% =

A
75/10

B
2/3

C
3/4

D
3/5
Mathematics
1 answer:
stiks02 [169]2 years ago
5 0

Answer:

Definitely 3/4!

Step-by-step explanation:

Option A = 7.5

Option B = 66.6%

Option C = 75% (because 25 times 4 is equal to 100%, so 25 times 3 would be 75)

Option D = 6/10 or 60%

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Solve 0.09 divided by 0.3
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Answer:

0.3.

Step-by-step explanation:

0.3|0.09

move the decimal over once on both sides.

03|.9

     3

03.|.9

   -   9

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4 0
3 years ago
The letters from the word “integer” are placed on cards and put in a hat. If someone picks 1 card out of the hat, how many diffe
vesna_86 [32]
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hope this help
7 0
3 years ago
Multiply and Simplify<br> (x-4)(x^2 - 5x - 6)
kirill [66]

Answer:

x^3 -9x^2 +14x +24

Step-by-step explanation:

(x-4)(x^2 - 5x - 6)

Multiply the x by everything in the second term

x * (x^2 - 5x - 6)

x^3 -5x^2 -6x

Multiply the -4 by everything in the second term

-4 * (x^2 - 5x - 6)

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Add everything together

I like to line them up vertically

x^3 -5x^2 -6x

      -4x^2 +20x +24

-------------------------------

x^3 -9x^2 +14x +24


4 0
2 years ago
Read 2 more answers
The overhead reach distances of adult females are normally distributed with a mean of 205 cm and a standard deviation of 7.8 cm.
devlian [24]

Answer:

Given the mean = 205 cm and standard deviation as 7.8cm

a. To calculate the probability that an individual distance is greater than 218.4 cm, we subtract the probability of the distance given (i.e 218.4 cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) from 1. Therefore, we have 1- P(Z\leq 1.72). Using the Z distribution table we have 1-0.9573. Therefore P(X >218.4)= 0.0427.

b. To calculate the probability that mean of 15 (i.e n=15) randomly selected distances is greater than 202.8, we subtract the probability of the distance given (i.e 202.8cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) divided by the square root of mean (i.e n= 15)  from 1. Therefore, we have 1- P(Z\leq -1.09). Using the Z distribution table we have 1-0.1378. Therefore P(X >202.8)= 0.8622.

c. This will also apply to a normally distributed data even if it is not up to the sample size of 30 since the sample distribution is not a skewed one.

Step-by-step explanation:

Given the mean = 205 cm and standard deviation as 7.8cm

a. To calculate the probability that an individual distance is greater than 218.4 cm, we subtract the probability of the distance given (i.e 218.4 cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) from 1. Therefore, we have 1- P(Z\leq 1.72). Using the Z distribution table we have 1-0.9573. Therefore P(X >218.4)= 0.0427.

b. To calculate the probability that mean of 15 (i.e n=15) randomly selected distances is greater than 202.8, we subtract the probability of the distance given (i.e 202.8cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) divided by the square root of mean (i.e n= 15)  from 1. Therefore, we have 1- P(Z\leq -1.09). Using the Z distribution table we have 1-0.1378. Therefore P(X >202.8)= 0.8622.

c. This will also apply to a normally distributed data even if it is not up to the sample size of 30 since the sample distribution is not a skewed one.

4 0
3 years ago
Work out 60 × 2/3 (2 over 3)
Taya2010 [7]
Solution:
60 x 2/3
60/1 x 2/3 
120/3
40 
Answer:
40

hope this helps!

3 0
3 years ago
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