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sertanlavr [38]
2 years ago
11

Please help I’m honestly gonna cry lol

Mathematics
1 answer:
BARSIC [14]2 years ago
6 0

Answer: 2z-15

Step-by-step explanation

Based on the visual image, AD is a line where a point O intersects somewhere on the line. AD is represented as 3z-11, while the segment from AO is represented as z+4.

In order to find the answer, we must subtract the entire line (AD) from AO in order to find the missing segment OD.

AD    -  AO   = OD

(3z-11) -  (z+4) = OD

Distribute the negative sign so it becomes:

(3z-11) -z - 4 = OD

Now combine like terms.

(3z-z) +(- 11 -4)= OD

2z - 15 = OD

And that is your answer!

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Simplify negative 7 and 1 over 8 − negative 9 and 1 over 2
Kryger [21]

Answer:

You can put it into 3 forms:

Exact form: 19/8

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Mixed Number Form: 2 3/8

4 0
3 years ago
Read 2 more answers
How do you illustrate<br>quadratic equation<br>in one variable?​
soldi70 [24.7K]

Step-by-step explanation:

Quadratic Equation

Quadratic equation is in the form

ax2+bx+c=0

Where

a, b, & c = real-number constants

a & b = numerical coefficient or simply coefficients

a = coefficient of x2

b = coefficient of x

c = constant term or simply constant

a cannot be equal to zero while either b or c can be zero

Examples of Quadratic Equation

Some quadratic equation may not look like the one above. The general appearance of quadratic equation is a second degree curve so that the degree power of one variable is twice of another variable. Below are examples of equations that can be considered as quadratic.

1. 3x2+2x−8=0

2. x2−9=0

3. 2x2+5x=0

4. sin2θ−2sinθ−1=0

5. x−5x−−√+6=0

6. 10x1/3+x1/6−2=0

7. 2lnx−−−√−5lnx−−−√4−7=0

For us to see that the above examples can be treated as quadratic equation, we take example no. 6 above, 10x1/3 + x1/6 - 2 = 0. Let x1/6 = z, thus, x1/3 = z2. The equation can now be written in the form 10z2 + z - 2 = 0, which shows clearly to be quadratic equation.

Roots of a Quadratic Equation

The equation ax2 + bx + c = 0 can be factored into the form

(x−x1)(x−x2)=0

Where x1 and x2 are the roots of ax2 + bx + c = 0.

Quadratic Formula

For the quadratic equation ax2 + bx + c = 0,

x=−b±b2−4ac−−−−−−−√2a

See the derivation of quadratic formula here.

The quantity b2 - 4ac inside the radical is called discriminat.

• If b2 - 4ac = 0, the roots are real and equal.

• If b2 - 4ac > 0, the roots are real and unequal.

• If b2 - 4ac < 0, the roots are imaginary.

Sum and Product of Roots

If the roots of the quadratic equation ax2 + bx + c

= 0 are x1 and x2, then

Sum of roots

x1+x2=−ba

Product of roots

x1x2=ca

You may see the derivation of formulas for sum and product of roots here.

4 0
3 years ago
Can you please help?
tigry1 [53]

Step-by-step explanation:

f/p = p(1+i)^n

p= 2500

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5 0
3 years ago
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PAIesung
Svetllana [295]

Answer:

The sale price was 60% of the purchase price.

Step-by-step explanation:

Given that Blake bought a motorcycle for $ 550 last year and sold it for $ 330 this year, to determine what is his sale price as a percentage of his purchase price, the following calculation must be performed:

550 = 100

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330 x 100/550 = X

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60 = X

Therefore, the sale price was 60% of the purchase price.

5 0
3 years ago
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