Answer:
P = 0.006
Step-by-step explanation:
Given
n = 25 Lamps
each with mean lifetime of 50 hours and standard deviation (SD) of 4 hours
Find probability that the lamp will be burning at end of 1300 hours period.
As we are not given that exact lamp, it means we have to find the probability where any of the lamp burning at the end of 1300 hours, So we have
Suppose i represents lamps
P (∑i from 1 to 25 (
> 1300)) = 1300
= P(
>
) where
represents mean time of a single lamp
= P (Z>
) Z is the standard normal distribution which can be found by using the formula
Z = Mean Time (
) - Life time of each Lamp (50 hours)/ (SD/
)
Z = (52-50)/(4/
) = 2.5
Now, P(Z>2.5) = 0.006 using the standard normal distribution table
Probability that a lamp will be burning at the end of 1300 hours period is 0.006
Answer:
(5/2 , 1)
Step-by-step explanation:
4X – 3y = 7
4x + y = 11
———————
Multiply a -1 to the bottom equation to get the 4x as a negative so it cancels out.
4x - 3y = 7
-4x - y = -11
——————
-4y = -4
Divide by -4
y = 1
Substitute the value of y into one of the equations and solve
4x - 3(1) = 7
4x -3 = 7
4x = 10
Divide by 4
X = 10/4
Simplify by dividing by 2
x = 5/2
Therefore the answer is (5/2, 1 )
Answer: Angles ABD and BAD (B)
Step-by-step explanation: Angles ABD BAD are not congruent angles, since they are the same angles.
Congruent angles are angles that both measure the same in degrees.
In this case, B is your correct answer since that answer has the same angle and not comparing any 2 angles, just the same one.
Hope This Helped, Have A Great Day!
Answer:with shock absorbers with light red yellow black grey orange
Step-by-step explanation:please give brainliest
Answer:
Step-by-step explanation:
We are asked to represent
as the product of the GCF and another sum.
First of all, we will find the greatest common factor of 18 and 24.
Factors of 18: 1, 2, 3, 6, 9, 18.
Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24.
We can see that greatest common factor of 18 and 24 is 6. Let us write our given expression as product.
Factor our 6:
Therefore, our required expression would be
.