Answer:
The slopes of three sides of triangle are as follows:
AB = -3
BC = 2/3
AC = -1/4
Step-by-step explanation:
The slope is denoted by m and is calculated using the formula

The given vertices are:
A(-2,4) B(-1,1) C(2,3)
The sides will be:
AB, BC, AC
Let m1 be the slope of AB
Let m2 be the slope of BC
Let m3 be the slope of AC
Now

Hence,
The slopes of three sides of triangle are as follows:
AB = -3
BC = 2/3
AC = -1/4
Answer:
Step-by-step explanation:
Well....if 1/7 liters of milk makes 1/6 of a jug
Then six times this must be a full jug....so
6*(1/7) =
6/7 liters of milk required
i hope this helps you happy holidays let me know if you need more information
Answer:
27 miles in the morning and 85 miles in the afternoon.
Explanation:
Let m be the number of miles they rode in the morning. They rode 4 more than 3 times this many in the afternoon; this gives us the expression
3m+4
to represent the miles ridden in the afternoon.
Together they rode 112 miles; this means we add the morning miles, m, to the afternoon miles, 3m+4, and get 112:
m+3m+4 = 112
Combine like terms:
4m+4 = 112
Subtract 4 from each side:
4m+4-4= 112-4
4m = 108
Divide both sides by 4:
4m/4 = 108/4
m = 27
They rode 27 miles in the morning.
That means in the afternoon, they rode
3m+4 = 3(27)+4 = 81+4 = 85 miles.
Answer:
10/16 (written as a fraction)
Step-by-step explanation:
Starting point
-(-2x+1)=9-14x
Solve the minus sign
2x-1=9-14x
Swap the Xs and the numbers, changing sign
2x+14x=9+1
Do calculations
16x=10
Result
x=10/16
Quadratic is in the form
ax^2+bx+c=0
so distribute and stuff and simplify
remember
a(b+c)=ab+ac
(x+2)^2+5(x+2)-6=0
remember order of opertaions
(x+2)(x+2)+5(x+2)-6=0
x^2+4x+4+5x+10-6=0
add like terms
x^2+9x+8=0