Let the faculties be X and the number of students be Y.
X/Y = 17/3
3X= 17Y
X=17Y/3
Let that be equation 1
We also know that X+Y = 740. Let it be equation 2
Substitute equation 1 in equation 2
(17Y/3)+Y= 740
20Y/3 = 740
Y=111
Since the total is 740, then X equal 740-111 =629.
The number of faculties is 111 and the number of students is 629.
Answer:
v = 0
Step-by-step explanation:
12 = 12 + v / 8
0 = 1/8v
v = 0



with that template in mind, let's see

so B went form 1 on f(x), down to 0.5 or 1/2 on g(x)
B = 1/2, thus the graph is stretched by twice as much.
So sig figs are non zero so
500 has 1 sig fig, 5
but 500. has 3 sig figs because it has a decimal
2.3 has 2 sig figs
2.03 has 3 sig figs so to make 232.76 to 2 sig figs you would put it into scientific notation and get 2.3 times 10^2 and thats 2 sig figs (the 10^2 doesn't count as a sig fig)