Hello!
![\large\boxed{c_{5} = 136}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7Bc_%7B5%7D%20%3D%20136%7D)
We can begin by solving for c₃ given the equations:
c₃ = 3c₂ + 2c₁ - 2
c₃ = 3(2) + 2(4) - 2
Simplify:
c₃ = 6 + 8 - 2 = 12
We can now find the subsequent terms:
c₄ = 3(12) + 2(2) - 2 = 38
c₅ = 3(38) + 2(12) - 2 = 136
Answer:
-1/4 (d+1)< 2
(d+1) × -1 < 2×4
(d+1) × -1 < 8
-d - 1 < 8
-d < 8 + 1
-d < 9
d > -9
d = { -8, -7, -6....., 0, 1, 2, 3, 4,....}
Step-by-step explanation:
brainliest plz
Answer:
Ok
Step-by-step explanation:
Answer:
x= 27.71281 = 16√3
y= 13.85641 = 8√3
Step-by-step explanation:
hope it helps :)
F(x) = 6(9)^x
f(1/2) = 6(9)^(1/2)
f(1/2) = 6(9)^(0.5)
f(1/2) = 6*(9^0.5) 9^0.5 = √9 = +3 or -3.
f(1/2) = 6*3 = 18 or 6*-3 = -18
f(1/2) = 18 or -18
Hope this helps.