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Katena32 [7]
4 years ago
13

Given cos0 = -2/3 and lies in quadrant lll what is the exact value of sin 0 in simplified form ?

Mathematics
1 answer:
aksik [14]4 years ago
6 0

Answer:

  sin(θ) = -(√5)/3

Step-by-step explanation:

In quadrant III, both sine and cosine are negative. Then the value of interest is ...

  sin(θ) = -√(1 - cos(θ)²) = -√(1 -4/9)

  sin(θ) = -(√5)/3

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