Given cos0 = -2/3 and lies in quadrant lll what is the exact value of sin 0 in simplified form ?
1 answer:
Answer:
sin(θ) = -(√5)/3
Step-by-step explanation:
In quadrant III, both sine and cosine are negative. Then the value of interest is ...
sin(θ) = -√(1 - cos(θ)²) = -√(1 -4/9)
sin(θ) = -(√5)/3
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