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3 years ago

Find the area of the hexagen whose Vertices taken in order

Mathematics

1 answer:

lakkis [162]3 years ago

4 0

Answer:

Step-by-step explanation:

A(5,0),B(4,2), C(1,3),D(-2,2),E(-3,-1),F(0-4)

we divide the hexagon in triangles and trapeziums

area Δ BCD (with coordinates B(4,2),C(1,3),D(-2,2)) =1/2(2+4)×2=6

area Δ DEG (with coordinates D(-2,2),E(-3,-1),G(-2.-2))=1/2(2+2)×2=4

area ΔAOF(with coordinates A(5,0),O(0,0),F(0,-4))=1/2×5×4=10

area trapezium ABDH (with coordinates A(5,0),B(4,2),D(-2,2),H(-2,0))=1/2[(2+5)+(2+4)]×2=13

area trapezium OHGF (with coordinates O(0,0),H(-2,0),G(-2,-2),F(0,-4))=1/2[4+2]×2=6

Total area=6+4+10+13+6=39 sq units.

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Nastasia [14]

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Step-by-step explanation:

Since f is an exponential function.

So, it is expressed as

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Since

$b=p(1+r)^1\\\\So,\\\\b=p(1+r)^{n\times \frac{1}{n}}\\\\b=(p(1+r)^n)^{\frac{1}{n}}\\\\b=c^{\frac{1}{n}}\\\\b^n=c$

Hence, a) $b= p(1 + r)^1$ b) $c= p(1 + r)^n$ c) $d= p(1 + r)^m$ d) $b^n=c$

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3 years ago

Find the distance between the point (2, 3) and the line 4x + 3y = 10 (round your answer to the nearest tenth).

Monica [59]

Explanation

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Using the distance formula we get:

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1 year ago

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Step-by-step explanation:

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